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hackercup / 2016 /finals /boomerang_crews.cpp
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2016 Problems
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// BOOMERANG CREWS
// Official Solution by Jacob Plachta
#define DEBUG 0
#include <algorithm>
#include <functional>
#include <numeric>
#include <iostream>
#include <iomanip>
#include <cstdio>
#include <cmath>
#include <complex>
#include <cstdlib>
#include <ctime>
#include <cstring>
#include <cassert>
#include <string>
#include <vector>
#include <list>
#include <map>
#include <set>
#include <deque>
#include <queue>
#include <stack>
#include <bitset>
#include <sstream>
using namespace std;
#define LL long long
#define LD long double
#define PR pair<int,int>
#define Fox(i,n) for (i=0; i<n; i++)
#define Fox1(i,n) for (i=1; i<=n; i++)
#define FoxI(i,a,b) for (i=a; i<=b; i++)
#define FoxR(i,n) for (i=(n)-1; i>=0; i--)
#define FoxR1(i,n) for (i=n; i>0; i--)
#define FoxRI(i,a,b) for (i=b; i>=a; i--)
#define Foxen(i,s) for (i=s.begin(); i!=s.end(); i++)
#define Min(a,b) a=min(a,b)
#define Max(a,b) a=max(a,b)
#define Sz(s) int((s).size())
#define All(s) (s).begin(),(s).end()
#define Fill(s,v) memset(s,v,sizeof(s))
#define pb push_back
#define mp make_pair
#define x first
#define y second
template<typename T> T Abs(T x) { return(x<0 ? -x : x); }
template<typename T> T Sqr(T x) { return(x*x); }
string plural(string s) { return(Sz(s) && s[Sz(s)-1]=='x' ? s+"en" : s+"s"); }
const int INF = (int)1e9;
const LD EPS = 1e-9;
const LD PI = acos(-1.0);
//#if DEBUG
#define GETCHAR getchar
/*#else
#define GETCHAR getchar_unlocked
#endif*/
bool Read(int &x)
{
char c,r=0,n=0;
x=0;
for(;;)
{
c=GETCHAR();
if ((c<0) && (!r))
return(0);
if ((c=='-') && (!r))
n=1;
else
if ((c>='0') && (c<='9'))
x=x*10+c-'0',r=1;
else
if (r)
break;
}
if (n)
x=-x;
return(1);
}
int main()
{
if (DEBUG)
freopen("in.txt","r",stdin);
int T,t;
int N,M,D;
int i,j,c,free;
int r1,r2,m;
static int A[100000],B[100000];
set<PR> S;
set<PR>::iterator I;
Read(T);
Fox1(t,T)
{
Read(N),Read(M),Read(D);
Fox(i,N)
Read(A[i]);
Fox(i,M)
Read(B[i]);
sort(A,A+N);
reverse(A,A+N);
j=free=0;
Fox(i,M)
if (B[i]<=A[0])
free++;
else
B[j++]=B[i];
M=j;
sort(B,B+M);
r1=0,r2=min(N,M);
while (r2>r1)
{
m=(r1+r2+1)>>1;
S.clear();
Fox(i,m)
S.insert(mp(A[i]%D,i));
c=1;
Fox(i,m)
{
I=S.lower_bound(mp(B[i]%D,-1));
if (I==S.end())
I=S.begin();
j=A[I->y],S.erase(I);
c+=(B[i]-j+D-1)/D-1;
if (c>N-m)
goto Bad;
}
r1=m;
continue;
Bad:;
r2=m-1;
}
printf("Case #%d: %d\n",t,free+r1);
}
return(0);
}