context
stringlengths
28
393
answer
stringlengths
17
532
question
stringlengths
5
112
CREATE TABLE head (age INTEGER)
SELECT COUNT(*) FROM head WHERE age > 56
部门中有多少人年龄大于56岁?
CREATE TABLE head (age VARCHAR, name VARCHAR, born_state VARCHAR)
SELECT name, born_state, age FROM head ORDER BY age
列出按年龄排序的部门负责人的姓名、出生地和年龄。
CREATE TABLE department (name VARCHAR, budget_in_billions VARCHAR, creation VARCHAR)
SELECT creation, name, budget_in_billions FROM department
列出每个部门的创建年份、名称和预算。
CREATE TABLE department (budget_in_billions INTEGER)
SELECT MAX(budget_in_billions), MIN(budget_in_billions) FROM department
部门的最高预算和最低预算是多少?
CREATE TABLE department (num_employees INTEGER, ranking INTEGER)
SELECT AVG(num_employees) FROM department WHERE ranking BETWEEN 10 AND 15
排名在10到15之间的部门的平均雇员人数是多少?
CREATE TABLE head (name VARCHAR, born_state VARCHAR)
SELECT name FROM head WHERE born_state <> '浙江'
出生在“浙江”州以外的人的名字是什么?
CREATE TABLE department (department_id VARCHAR, creation VARCHAR), CREATE TABLE management (department_id VARCHAR, head_id VARCHAR), CREATE TABLE head (head_id VARCHAR, born_state VARCHAR)
SELECT DISTINCT T1.creation FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T3.born_state = '河南'
出生于“河南”州的秘书所管理的各部门的不同创建年份是什么?
CREATE TABLE head (born_state VARCHAR)
SELECT born_state FROM head GROUP BY born_state HAVING COUNT(*) >= 3
至少有3个负责人出生的州的名字是什么?
CREATE TABLE department (creation VARCHAR)
SELECT creation FROM department GROUP BY creation ORDER BY COUNT(*) DESC LIMIT 1
大多数部门在哪一年成立?
CREATE TABLE department (department_id VARCHAR, num_employees VARCHAR, name VARCHAR), CREATE TABLE management (department_id VARCHAR, temporary_acting VARCHAR)
SELECT T1.name, T1.num_employees FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id WHERE T2.temporary_acting = '是'
显示由临时代理值为“是”的负责人所管理的部门的员工姓名和数目?
CREATE TABLE management (temporary_acting VARCHAR)
SELECT COUNT(DISTINCT temporary_acting) FROM management
有多少个代理状态?
CREATE TABLE department (department_id VARCHAR), CREATE TABLE management (department_id VARCHAR)
SELECT COUNT(*) FROM department WHERE NOT department_id IN (SELECT department_id FROM management)
有多少部门由没有提到的负责人领导?
CREATE TABLE management (head_id VARCHAR, temporary_acting VARCHAR), CREATE TABLE head (age VARCHAR, head_id VARCHAR)
SELECT DISTINCT T1.age FROM management AS T2 JOIN head AS T1 ON T1.head_id = T2.head_id WHERE T2.temporary_acting = '是'
那些正在代理的负责人有哪些不同的年龄?
CREATE TABLE department (department_id VARCHAR, name VARCHAR), CREATE TABLE management (department_id VARCHAR, head_id VARCHAR), CREATE TABLE head (head_id VARCHAR, born_state VARCHAR)
SELECT T3.born_state FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T1.name = '财政部' INTERSECT SELECT T3.born_state FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T1.name = '国土安全部'
列出“财政部”部门秘书和“国土安全部”秘书出生的州。
CREATE TABLE management (department_id VARCHAR), CREATE TABLE department (department_id VARCHAR, name VARCHAR)
SELECT T1.department_id, T1.name, COUNT(*) FROM management AS T2 JOIN department AS T1 ON T1.department_id = T2.department_id GROUP BY T1.department_id HAVING COUNT(*) > 1
哪个部门有不止一个负责人?列出ID、姓名和人数。
CREATE TABLE head (head_id VARCHAR, name VARCHAR)
SELECT head_id, name FROM head WHERE name LIKE '强'
哪个负责人的名字有“强”这个子串?列出ID和姓名。
CREATE TABLE farm (Id VARCHAR)
SELECT COUNT(*) FROM farm
那里有多少个农场?
CREATE TABLE farm (Id VARCHAR)
SELECT COUNT(*) FROM farm
计算农场的数量。
CREATE TABLE farm (Total_Horses VARCHAR)
SELECT Total_Horses FROM farm ORDER BY Total_Horses ASC
按升序列出农场里的马的总数。
CREATE TABLE farm (Total_Horses VARCHAR)
SELECT Total_Horses FROM farm ORDER BY Total_Horses ASC
按照升序排列,每一个农场的马的总数是什么?
CREATE TABLE farm_competition (Hosts VARCHAR, Theme VARCHAR)
SELECT Hosts FROM farm_competition WHERE Theme <> '外星人'
什么主持人所主持比赛的主题不是“外星人”?
CREATE TABLE farm_competition (Hosts VARCHAR, Theme VARCHAR)
SELECT Hosts FROM farm_competition WHERE Theme <> '外星人'
返回主题不是“外星人”的竞赛的主持人?
CREATE TABLE farm_competition (Theme VARCHAR, YEAR VARCHAR)
SELECT Theme FROM farm_competition ORDER BY YEAR ASC
按年份排序的农场比赛的主题是什么?
CREATE TABLE farm_competition (Theme VARCHAR, YEAR VARCHAR)
SELECT Theme FROM farm_competition ORDER BY YEAR ASC
返回农场比赛的主题,按年份排序。
CREATE TABLE farm (Total_Horses INTEGER, Working_Horses INTEGER)
SELECT AVG(Working_Horses) FROM farm WHERE Total_Horses > 5000
拥有超过5000匹马的农场中,平均的工作马的数量是多少?
CREATE TABLE farm (Total_Horses INTEGER, Working_Horses INTEGER)
SELECT AVG(Working_Horses) FROM farm WHERE Total_Horses > 5000
给出有5000多匹马的农场的平均工作马的数量。
CREATE TABLE farm (Cows INTEGER)
SELECT MAX(Cows), MIN(Cows) FROM farm
所有农场中,奶牛的最大和最小数量是多少?
CREATE TABLE farm (Cows INTEGER)
SELECT MAX(Cows), MIN(Cows) FROM farm
返回所有农场奶牛的最大和最小数量。
CREATE TABLE city (Status VARCHAR)
SELECT COUNT(DISTINCT Status) FROM city
城市有多少种不同的地位?
CREATE TABLE city (Status VARCHAR)
SELECT COUNT(DISTINCT Status) FROM city
统计不同地位的数量。
CREATE TABLE city (Official_Name VARCHAR, Population VARCHAR)
SELECT Official_Name FROM city ORDER BY Population DESC
按人口降序列出城市的官方名称。
CREATE TABLE city (Official_Name VARCHAR, Population VARCHAR)
SELECT Official_Name FROM city ORDER BY Population DESC
按人口降序排列的城市的官方名称是什么?
CREATE TABLE city (Official_Name VARCHAR, Population VARCHAR, Status VARCHAR)
SELECT Official_Name, Status FROM city ORDER BY Population DESC LIMIT 1
列出人口最多的城市的官方名称和状态。
CREATE TABLE city (Official_Name VARCHAR, Population VARCHAR, Status VARCHAR)
SELECT Official_Name, Status FROM city ORDER BY Population DESC LIMIT 1
居住人数最多的城市的官方名称和状态是什么?
CREATE TABLE city (City_ID VARCHAR, Official_Name VARCHAR), CREATE TABLE farm_competition (Host_city_ID VARCHAR, Year VARCHAR)
SELECT T2.Year, T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID
展示主办比赛城市的年份和正式名称。
CREATE TABLE city (City_ID VARCHAR, Official_Name VARCHAR), CREATE TABLE farm_competition (Host_city_ID VARCHAR, Year VARCHAR)
SELECT T2.Year, T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID
给出每个竞赛的城市的年份和官方名称。
CREATE TABLE city (City_ID VARCHAR, Official_Name VARCHAR), CREATE TABLE farm_competition (Host_city_ID VARCHAR)
SELECT T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID HAVING COUNT(*) > 1
展示举办了不止一次比赛的城市的官方名称。
CREATE TABLE city (City_ID VARCHAR, Official_Name VARCHAR), CREATE TABLE farm_competition (Host_city_ID VARCHAR)
SELECT T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID HAVING COUNT(*) > 1
举办了不止一次比赛的城市的官方名称是什么?
CREATE TABLE city (City_ID VARCHAR, Status VARCHAR), CREATE TABLE farm_competition (Host_city_ID VARCHAR)
SELECT T1.Status FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID ORDER BY COUNT(*) DESC LIMIT 1
展示主办城市数量最多的城市的状态。
CREATE TABLE city (City_ID VARCHAR, Status VARCHAR), CREATE TABLE farm_competition (Host_city_ID VARCHAR)
SELECT T1.Status FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID ORDER BY COUNT(*) DESC LIMIT 1
主办过最多比赛的城市的状态如何?
CREATE TABLE city (City_ID VARCHAR, Population INTEGER), CREATE TABLE farm_competition (Host_city_ID VARCHAR, Theme VARCHAR)
SELECT T2.Theme FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID WHERE T1.Population > 1000
请显示拥有超过1000人的主办城市的比赛主题。
CREATE TABLE city (City_ID VARCHAR, Population INTEGER), CREATE TABLE farm_competition (Host_city_ID VARCHAR, Theme VARCHAR)
SELECT T2.Theme FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID WHERE T1.Population > 1000
有超过1000居民的主办城市的比赛主题是什么?
CREATE TABLE city (Population INTEGER, Status VARCHAR)
SELECT Status, AVG(Population) FROM city GROUP BY Status
请显示不同城市的地位和各个地位的城市平均人口。
CREATE TABLE city (Population INTEGER, Status VARCHAR)
SELECT Status, AVG(Population) FROM city GROUP BY Status
每个城市的状态和平均人口是多少?
CREATE TABLE city (Status VARCHAR)
SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) ASC
请按每个状态的城市的数量排列,显示不同的状态。
CREATE TABLE city (Status VARCHAR)
SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) ASC
返回城市的不同状态,按频率递增排序。
CREATE TABLE city (Status VARCHAR)
SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) DESC LIMIT 1
列出城市中最常见的一种状态。
CREATE TABLE city (Status VARCHAR)
SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) DESC LIMIT 1
在所有城市中最常见的状态是什么?
CREATE TABLE city (City_ID VARCHAR, Official_Name VARCHAR, Host_city_ID VARCHAR), CREATE TABLE farm_competition (City_ID VARCHAR, Official_Name VARCHAR, Host_city_ID VARCHAR)
SELECT Official_Name FROM city WHERE NOT City_ID IN (SELECT Host_city_ID FROM farm_competition)
列出没有比赛的城市的官方名称。
CREATE TABLE city (City_ID VARCHAR, Official_Name VARCHAR, Host_city_ID VARCHAR), CREATE TABLE farm_competition (City_ID VARCHAR, Official_Name VARCHAR, Host_city_ID VARCHAR)
SELECT Official_Name FROM city WHERE NOT City_ID IN (SELECT Host_city_ID FROM farm_competition)
没有举办过农场比赛的城市的官方名称是什么?
CREATE TABLE city (Population INTEGER, Status VARCHAR)
SELECT Status FROM city WHERE Population > 1500 INTERSECT SELECT Status FROM city WHERE Population < 500
显示人口大于1500和小于500的城市的状态。
CREATE TABLE city (Population INTEGER, Status VARCHAR)
SELECT Status FROM city WHERE Population > 1500 INTERSECT SELECT Status FROM city WHERE Population < 500
人口超过1500的城市和人口低于500的城市,其状态分别是什么?
CREATE TABLE city (Official_Name VARCHAR, Population INTEGER)
SELECT Official_Name FROM city WHERE Population > 1500 OR Population < 500
查找人口大于1500或小于500的城市的官方名称。
CREATE TABLE city (Official_Name VARCHAR, Population INTEGER)
SELECT Official_Name FROM city WHERE Population > 1500 OR Population < 500
人口超过1500或少于500的城市的官方名称是什么?
CREATE TABLE city (Status VARCHAR, Census_Ranking VARCHAR)
SELECT Census_Ranking FROM city WHERE Status <> "乡村"
显示不属于“乡村”的城市的人口普查排名。
CREATE TABLE city (Status VARCHAR, Census_Ranking VARCHAR)
SELECT Census_Ranking FROM city WHERE Status <> "乡村"
没有“乡村”状态的城市的人口普查排名是多少?
CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR), CREATE TABLE student_course_registrations (course_Id VARCHAR)
SELECT T1.course_name FROM courses AS T1 JOIN student_course_registrations AS T2 ON T1.course_id = T2.course_Id GROUP BY T1.course_id ORDER BY COUNT(*) DESC LIMIT 1
注册学生最多的是哪门课程?
CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR), CREATE TABLE student_course_registrations (course_Id VARCHAR)
SELECT T1.course_name FROM courses AS T1 JOIN student_course_registrations AS T2 ON T1.course_id = T2.course_Id GROUP BY T1.course_id ORDER BY COUNT(*) DESC LIMIT 1
最多注册学生的课程名称是什么?
CREATE TABLE student_course_registrations (student_id VARCHAR)
SELECT student_id FROM student_course_registrations GROUP BY student_id ORDER BY COUNT(*) LIMIT 1
注册一些课程但注册课程最少的学生的ID是什么?
CREATE TABLE student_course_registrations (student_id VARCHAR)
SELECT student_id FROM student_course_registrations GROUP BY student_id ORDER BY COUNT(*) LIMIT 1
注册课程数量最少但是注册了一些课程的学生的ID是什么?
CREATE TABLE candidates (candidate_id VARCHAR), CREATE TABLE people (first_name VARCHAR, last_name VARCHAR, person_id VARCHAR)
SELECT T2.first_name, T2.last_name FROM candidates AS T1 JOIN people AS T2 ON T1.candidate_id = T2.person_id
所有候选人的名字和姓氏是什么?
CREATE TABLE candidates (candidate_id VARCHAR), CREATE TABLE people (first_name VARCHAR, last_name VARCHAR, person_id VARCHAR)
SELECT T2.first_name, T2.last_name FROM candidates AS T1 JOIN people AS T2 ON T1.candidate_id = T2.person_id
所有候选人的名字和姓氏是什么?
CREATE TABLE students (student_id VARCHAR), CREATE TABLE student_course_attendance (student_id VARCHAR)
SELECT student_id FROM students WHERE NOT student_id IN (SELECT student_id FROM student_course_attendance)
列出从不上课的学生的ID?
CREATE TABLE students (student_id VARCHAR), CREATE TABLE student_course_attendance (student_id VARCHAR)
SELECT student_id FROM students WHERE NOT student_id IN (SELECT student_id FROM student_course_attendance)
每一个从未上过课的学生的ID是什么?
CREATE TABLE student_course_attendance (student_id VARCHAR)
SELECT student_id FROM student_course_attendance
列出参加过一些课程的学生的ID?
CREATE TABLE student_course_attendance (student_id VARCHAR)
SELECT student_id FROM student_course_attendance
所有参加过至少一门课程的学生的ID是什么?
CREATE TABLE student_course_registrations (course_id VARCHAR, student_id VARCHAR), CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR)
SELECT T1.student_id, T2.course_name FROM student_course_registrations AS T1 JOIN courses AS T2 ON T1.course_id = T2.course_id
所有上课学生ID是什么?这些课程的名称是什么?
CREATE TABLE student_course_registrations (student_id VARCHAR, registration_date VARCHAR), CREATE TABLE students (student_id VARCHAR, student_details VARCHAR)
SELECT T2.student_details FROM student_course_registrations AS T1 JOIN students AS T2 ON T1.student_id = T2.student_id ORDER BY T1.registration_date DESC LIMIT 1
最近注册课程的学生的具体信息是什么?
CREATE TABLE student_course_registrations (student_id VARCHAR, registration_date VARCHAR), CREATE TABLE students (student_id VARCHAR, student_details VARCHAR)
SELECT T2.student_details FROM student_course_registrations AS T1 JOIN students AS T2 ON T1.student_id = T2.student_id ORDER BY T1.registration_date DESC LIMIT 1
关于最近注册课程的学生,我们有哪些信息?
CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR), CREATE TABLE student_course_attendance (course_id VARCHAR)
SELECT COUNT(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = "英语"
有多少学生参加英语课程?
CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR), CREATE TABLE student_course_attendance (course_id VARCHAR)
SELECT COUNT(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = "英语"
参加英语课程的有多少学生?
CREATE TABLE courses (course_id VARCHAR), CREATE TABLE student_course_attendance (course_id VARCHAR, student_id VARCHAR)
SELECT COUNT(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T2.student_id = 171
ID为171的学生参加了多少门课程?
CREATE TABLE courses (course_id VARCHAR), CREATE TABLE student_course_attendance (course_id VARCHAR, student_id VARCHAR)
SELECT COUNT(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T2.student_id = 171
ID 171的学生实际参加了多少门课程?
CREATE TABLE people (email_address VARCHAR, person_id VARCHAR), CREATE TABLE candidates (candidate_id VARCHAR)
SELECT T2.candidate_id FROM people AS T1 JOIN candidates AS T2 ON T1.person_id = T2.candidate_id WHERE T1.email_address = "stanley.monahan@example.org"
找到电子邮箱为“stanley.monahan@example.org”的候选人的ID。
CREATE TABLE people (email_address VARCHAR, person_id VARCHAR), CREATE TABLE candidates (candidate_id VARCHAR)
SELECT T2.candidate_id FROM people AS T1 JOIN candidates AS T2 ON T1.person_id = T2.candidate_id WHERE T1.email_address = "stanley.monahan@example.org"
候选人的ID是什么,他的电子邮件是“stanley.monahan@example.org”?
CREATE TABLE candidate_assessments (assessment_date VARCHAR, candidate_id VARCHAR)
SELECT candidate_id FROM candidate_assessments ORDER BY assessment_date DESC LIMIT 1
找到最近访问课程的候选人的ID?
CREATE TABLE candidate_assessments (assessment_date VARCHAR, candidate_id VARCHAR)
SELECT candidate_id FROM candidate_assessments ORDER BY assessment_date DESC LIMIT 1
最近访问课程的候选人的ID是什么?
CREATE TABLE students (student_id VARCHAR, student_details VARCHAR), CREATE TABLE student_course_registrations (student_id VARCHAR)
SELECT T1.student_details FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
注册最多课程的学生的具体信息是什么?
CREATE TABLE students (student_id VARCHAR, student_details VARCHAR), CREATE TABLE student_course_registrations (student_id VARCHAR)
SELECT T1.student_details FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
注册课程最多的学生的详细情况是什么?
CREATE TABLE students (student_id VARCHAR), CREATE TABLE student_course_registrations (student_id VARCHAR)
SELECT T1.student_id, COUNT(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id
列出注册一些课程的学生的ID和注册课程的数量?
CREATE TABLE students (student_id VARCHAR), CREATE TABLE student_course_registrations (student_id VARCHAR)
SELECT T1.student_id, COUNT(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id
对于每个注册了某些课程的学生,他们注册了多少课程?
CREATE TABLE students (student_id VARCHAR), CREATE TABLE student_course_registrations (course_id VARCHAR, student_id VARCHAR), CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR)
SELECT T3.course_name, COUNT(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id JOIN courses AS T3 ON T2.course_id = T3.course_id GROUP BY T2.course_id
每门课程有多少注册学生?列出课程名称和注册的学生人数?
CREATE TABLE students (student_id VARCHAR), CREATE TABLE student_course_registrations (course_id VARCHAR, student_id VARCHAR), CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR)
SELECT T3.course_name, COUNT(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id JOIN courses AS T3 ON T2.course_id = T3.course_id GROUP BY T2.course_id
对于每个课程ID,注册了多少学生,课程名称是什么?
CREATE TABLE candidate_assessments (candidate_id VARCHAR, asessment_outcome_code VARCHAR)
SELECT candidate_id FROM candidate_assessments WHERE asessment_outcome_code = "通过"
找到评估码为“通过”的候选人ID?
CREATE TABLE candidate_assessments (candidate_id VARCHAR, asessment_outcome_code VARCHAR)
SELECT candidate_id FROM candidate_assessments WHERE asessment_outcome_code = "通过"
成绩代码为及格的候选人的ID是什么?
CREATE TABLE candidates (candidate_id VARCHAR), CREATE TABLE candidate_assessments (candidate_id VARCHAR, asessment_outcome_code VARCHAR), CREATE TABLE people (cell_mobile_number VARCHAR, person_id VARCHAR)
SELECT T3.cell_mobile_number FROM candidates AS T1 JOIN candidate_assessments AS T2 ON T1.candidate_id = T2.candidate_id JOIN people AS T3 ON T1.candidate_id = T3.person_id WHERE T2.asessment_outcome_code = "失败"
查找评估代码是“失败”的考生的手机号码?
CREATE TABLE candidates (candidate_id VARCHAR), CREATE TABLE candidate_assessments (candidate_id VARCHAR, asessment_outcome_code VARCHAR), CREATE TABLE people (cell_mobile_number VARCHAR, person_id VARCHAR)
SELECT T3.cell_mobile_number FROM candidates AS T1 JOIN candidate_assessments AS T2 ON T1.candidate_id = T2.candidate_id JOIN people AS T3 ON T1.candidate_id = T3.person_id WHERE T2.asessment_outcome_code = "失败"
收到“失败”评估码的候选人的手机号码是多少?
CREATE TABLE student_course_attendance (course_id VARCHAR, student_id VARCHAR)
SELECT student_id FROM student_course_attendance WHERE course_id = 301
那些注册301课程的学生的ID是什么?
CREATE TABLE student_course_attendance (course_id VARCHAR, student_id VARCHAR)
SELECT student_id FROM student_course_attendance WHERE course_id = 301
注册301课程的学生的ID是什么?
CREATE TABLE student_course_attendance (date_of_attendance VARCHAR, course_id VARCHAR, student_id VARCHAR)
SELECT student_id FROM student_course_attendance WHERE course_id = 301 ORDER BY date_of_attendance DESC LIMIT 1
最近注册301课程的学生的ID是什么?
CREATE TABLE student_course_attendance (date_of_attendance VARCHAR, course_id VARCHAR, student_id VARCHAR)
SELECT student_id FROM student_course_attendance WHERE course_id = 301 ORDER BY date_of_attendance DESC LIMIT 1
对于最近注册301课程的学生,他们的ID是什么?
CREATE TABLE addresses (city VARCHAR, address_id VARCHAR), CREATE TABLE people_addresses (address_id VARCHAR)
SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id
找到人的地址的不同城市?
CREATE TABLE addresses (city VARCHAR, address_id VARCHAR), CREATE TABLE people_addresses (address_id VARCHAR)
SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id
人们居住的不同城市有哪些?
CREATE TABLE addresses (city VARCHAR, address_id VARCHAR), CREATE TABLE people_addresses (person_id VARCHAR, address_id VARCHAR), CREATE TABLE students (student_id VARCHAR)
SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id JOIN students AS T3 ON T2.person_id = T3.student_id
找出学生地址的不同城市?
CREATE TABLE addresses (city VARCHAR, address_id VARCHAR), CREATE TABLE people_addresses (person_id VARCHAR, address_id VARCHAR), CREATE TABLE students (student_id VARCHAR)
SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id JOIN students AS T3 ON T2.person_id = T3.student_id
学生居住的不同城市有哪些?
CREATE TABLE courses (course_name VARCHAR)
SELECT course_name FROM courses ORDER BY course_name
按字母顺序列出课程名称?
CREATE TABLE courses (course_name VARCHAR)
SELECT course_name FROM courses ORDER BY course_name
按字母顺序排列的课程名称是什么?
CREATE TABLE people (first_name VARCHAR)
SELECT first_name FROM people ORDER BY first_name
按字母顺序列出人的名字?
CREATE TABLE people (first_name VARCHAR)
SELECT first_name FROM people ORDER BY first_name
按字母顺序排列的人的名字是什么?
CREATE TABLE student_course_registrations (student_id VARCHAR), CREATE TABLE student_course_attendance (student_id VARCHAR)
SELECT student_id FROM student_course_registrations UNION SELECT student_id FROM student_course_attendance
注册课程或参加课程的学生的ID是什么?