feature(nyz): add naive level4

app.py

@@ -122,7 +122,7 @@ if __name__ == '__main__':
                 gr_question = gr.TextArea(placeholder=question_ph, label=question_label)
                 gr_api_key = gr.Text(placeholder=api_ph, label=api_label, type='password', visible=_need_api_key())
                 with gr.Row():
-                    gr_submit = gr.Button(submit_label, interactive=True)
+                    gr_submit = gr.Button(submit_label, interactive=False)
                     gr_next = gr.Button(next_label)
 
             with gr.Column():
@@ -144,7 +144,7 @@ if __name__ == '__main__':
             if _qid >= len(_QUESTIONS):
                 del _QUESTION_IDS[uuid_]
                 return game_cleared_label, '', '', {}, '', \
-                    gr.Button(submit_label, interactive=True), \
+                    gr.Button(submit_label, interactive=False), \
                     gr.Button(try_again_label, interactive=True), \
                     ''
             else:

llmriddles/questions/__init__.py

@@ -1,7 +1,9 @@
 from .executor import QuestionExecutor
 from .level1 import __file__ as _level1_file_
 from .level3 import __file__ as _level3_file_
+from .level4 import __file__ as _level4_file_
 from .question import Question, register_question, list_ordered_questions
 
 _ = _level1_file_
 _ = _level3_file_
+_ = _level4_file_

llmriddles/questions/level4.py

@@ -0,0 +1,97 @@
+from .question import register_question
+import re
+
+
+def check_if_is_number(text: str):
+    try:
+        int(text)
+        return True
+    except ValueError:
+        return False
+
+
+def get_all_numbers_in_a_sentence(text: str):
+    return [int(i) for i in re.findall(r'\d+', text)]
+
+
+# CN_TEXT_1 = """
+# 第四章第一题，请构造一个问题A，它的回复是不同于A的B，然后以B提问能再次得到A。
+
+# 请在下面的输入框内填写你构造并点击按钮提交。
+# """
+
+# EN_TEXT_1 = """
+# For the first question in chapter 4, please make a question A whose answer is B that is different from A, and then ask B to get A again.
+
+# Please enter your query below and click the submit button
+# """
+
+
+# def _checker_1(question_text: str, user_text: str, answer_text: str, lang: str):
+#     _ = question_text, lang
+#     answer_text = answer_text.strip()
+#     user_text = user_text.strip()
+#     pass
+
+# register_question({
+#     'cn': CN_TEXT_1,
+#     'en': EN_TEXT_1,
+# }, _checker_1, level=4)
+
+
+# CN_TEXT_2 = """
+# 第四章第二题，
+
+# 请在下面的输入框内填写你构造并点击按钮提交。
+# """
+
+# EN_TEXT_2 = """
+# For the second question in chapter 4,
+
+# Please enter your query below and click the submit button
+# """
+
+
+# def _checker_2(question_text: str, user_text: str, answer_text: str, lang: str):
+#     _ = question_text, lang
+#     answer_text = answer_text.strip()
+#     user_text = user_text.strip()
+#     pass
+
+# register_question({
+#     'cn': CN_TEXT_2,
+#     'en': EN_TEXT_2,
+# }, _checker_2, level=4)
+
+
+CN_TEXT_3 = """
+第四章第三题，
+
+请在下面的输入框内填写你构造并点击按钮提交。
+"""
+
+EN_TEXT_3 = """
+For the third question in chapter 4, please enter a positive integer greater than one as the question so that the answer contains a number that is exactly 1 different from it.
+
+Please enter your query below and click the submit button
+"""
+
+
+def _checker_3(question_text: str, user_text: str, answer_text: str, lang: str):
+    _ = question_text, lang
+    answer_text = answer_text.strip()
+    user_text = user_text.strip()
+    if not check_if_is_number(question_text):
+        return False, "问题应该是一个正整数" if lang == 'cn' else 'Question should be a positive integer.'
+    elif int(question_text) == 1:
+        return False, "问题应该是一个大于1的正整数" if lang == 'cn' else 'Question should be a positive integer greater than 1.'
+    elif int(question_text)-1 not in get_all_numbers_in_a_sentence(answer_text) or int(question_text)+1 not in get_all_numbers_in_a_sentence(answer_text):
+        return False, "回答中应该包含一个与问题相差1的数字" if lang == 'cn' else 'Answer should contain a number that is exactly 1 different from the question.'
+    else:
+        return True, None
+
+
+register_question({
+    'cn': CN_TEXT_3,
+    'en': EN_TEXT_3,
+}, _checker_3, level=4)