update readme

README.md

@@ -27,7 +27,7 @@ It's also fine not to use this prompt. It won't significantly impact the effecti
 
 ## Goal: Ice-breaking!
 
-The choice of the acronym "ICE" for ICE-GRT is deliberate. It represents our aspiration to catalyze an 'ice-breaking' moment in the research of LLMs.This reflects our hope to encourage researchers to explore and realize the broad possibilities of ICE-GRT in a range of tasks. We aim to pave the way for novel discoveries and advancements in the field, demonstrating that the capabilities of our model are as extensive and varied as they are innovative.
+The choice of the acronym "ICE" for ICE-GRT is deliberate. It represents our aspiration to catalyze an 'ice-breaking' moment in the research of LLMs. This reflects our hope to encourage researchers to explore and realize the broad possibilities of ICE-GRT in a range of tasks. We aim to pave the way for novel discoveries and advancements in the field, demonstrating that the capabilities of our model are as extensive and varied as they are innovative.
 
 
 ## Model Performance on 12 general Language Tasks
@@ -63,20 +63,26 @@ Sure, here's a Python function that counts the occurrences of each word in a giv
 ```python
 def count_words(text):
     words = text.lower().split()
-    word_counts = {}for word in words:if word in word_counts:
-            word_counts[word] += 1else:
-            word_counts[word] = 1return word_counts
+    word_counts = {}
+    for word in words:
+        if word in word_counts:
+            word_counts[word] += 1
+        else:
+            word_counts[word] = 1
+    return word_counts
 ```
 To sort the dictionary of word counts, you can use the sorted() function along with a lambda function that compares the values of the dictionary items:<br>
 ```python
 def sort_word_counts(word_counts):
-    sorted_counts = sorted(word_counts.items(), key=lambda x: x[1], reverse=True)return sorted_counts
+    sorted_counts = sorted(word_counts.items(), key=lambda x: x[1], reverse=True)
+    return sorted_counts
 ```
 Here's how you can use these functions together to count the occurrences of each word in a string and sort the word counts:<br>
 ```python
 text = "The quick brown fox jumped over the lazy dog. The dog barked at the fox."
 word_counts = count_words(text)
-sorted_word_counts = sort_word_counts(word_counts)print(sorted_word_counts)
+sorted_word_counts = sort_word_counts(word_counts)
+print(sorted_word_counts)
 ```
 This will output:<br>
 ```python
@@ -122,26 +128,27 @@ print(topics)
 ### Muilti-lingistic Task
 
 __Question 1:__ <br>
-生成一个5乘以5的表格，并且每一个element都+1递增。
+我很喜欢周杰伦的《简单爱》这首歌曲。可以帮我分析一下这首歌吗？
 
 __Response 1:__ <br>
-以下是一个5乘以5的表格，其中每个元素都递增1：<br>
-```
-1  2  3  4  5
-2  3  4  5  6
-3  4  5  6  7
-4  5  6  7  8
-5  6  7  8  9
-```
-你可以使用任何适合你的编程语言和工具来生成这样的表格。在Python中，你可以使用以下代码：
-```python
-for i in range(1, 6):
-    print(" ".join([str(i+1) for _ in range(5)]))
-```
-这将输出每一行的数字，从1开始，每一列的数字从1到5。
+当然可以。周杰伦的《简单爱》这首歌是一首抒情的流行歌曲，以简单的旋律和易于记忆的歌词著称。以下是对这首歌的一些分析：
+
+1.歌词：歌曲的歌词简单易懂，表达了简单的爱情，没有太多复杂的情感和抽象的比喻。歌词中的“简单爱”是指一种真实、纯粹的爱情，没有太多的承诺和纷乱的感情，而是一种简单而又深刻的感情体验。
+
+2.旋律：这首歌的旋律非常易于记忆，很快就能让人唱出来。旋律简单而优美，具有一种轻快的节奏感，让人感到快乐和舒适。
+
+3.编曲：这首歌的编曲非常简单，主要由钢琴、吉他和弦乐组成。钢琴和吉他的和声营造了一种温馨的氛围，弦乐则增加了歌曲的感染力和气氛。
+
+4.表现手法：这首歌的表现手法非常简单，主要是周杰伦的嗓音以及他的情感投入。周杰伦在演唱这首歌时，通过自然而然的呼吸、声调的变化和情感的表达，让人感到他真正地体验到了简单的爱情，并且让人产生共鸣。
+
+综上所述，《简单爱》这首歌是一首非常易于记忆、简单易懂、温馨感人的流行歌曲，通过周杰伦的演唱和简单的编曲，传递出了一种简单而真实的爱情感受。
+
+
+<br>
 
 ---
 
+
 __Question 2:__ <br>
 describe the panda in Chinese