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the hcf and lcm of two numbers m and n are respectively 8 and 200 . if m + n = 84 , then 1 / m + 1 / n is equal to | "there are several algebraic ways to solve this question , but the easiest way is as follows : since we can not have two correct answers just pick a prime greater than 11 , square it and see what would be the remainder upon division of it by 12 . n = 17 - - > n ^ 2 = 289 - - > remainder upon division 289 by 12 is 1 . answer : b ." | a ) 0 , b ) 1 , c ) 2 , d ) 3 , e ) 5 | b | subtract(power(add(11, 2), 2), multiply(12, const_4)) | add(n0,n1)|multiply(n2,const_4)|power(#0,n1)|subtract(#2,#1)| | general |
in a division sum , the remainder is 8 and the divisor is 6 times the quotient and is obtained by adding 3 to the thrice of the remainder . the dividend is : | "explanation : 3 * 5 + 5 * 3 = ( 2 * 3 - 3 * 5 + 3 * 5 ) + ( 2 * 5 - 3 * 3 + 5 * 3 ) = ( 6 + 10 - 9 + 15 ) = 22 . answer : a ) 22" | a ) 22 , b ) 37 , c ) 38 , d ) 398 , e ) 72 | a | add(multiply(2, 3), multiply(3, 5)) | multiply(n0,n1)|multiply(n1,n3)|add(#0,#1)| | general |
the number 70 can be written as the sum of the squares of 3 different positive integers . what is the sum of these 3 integers ? | "let ' s suppose that speed while returning was xkm / h since the distance is same , we can apply the formula of avg speed avg speed = 2 s 1 s 2 / s 1 + s 2 4 = 2 * 3 * x / 3 + x x = 6 b is the answer" | a ) 5.75 , b ) 6 , c ) 7.25 , d ) 7.5 , e ) 7.75 | b | divide(multiply(4, 3), subtract(multiply(const_2, 3), 4)) | multiply(n0,n1)|multiply(n0,const_2)|subtract(#1,n1)|divide(#0,#2)| | physics |
a cube of side 5.5 meter length is cut into small cubes of side 110 cm each . how many such small cubes can be obtained ? | x * y = constt . let x = y = 100 in beginning i . e . x * y = 100 * 100 = 10000 x ( 100 ) - - - becomes - - - > 1.4 x ( 140 ) i . e . 140 * new ' y ' = 10000 i . e . new ' y ' = 10000 / 140 = 71.43 i . e . y decreases from 100 to 71.43 i . e . decrease of 28.57 % c | a ) 34 % , b ) 36 % , c ) 28.57 % , d ) 30 % , e ) 32 % | c | multiply(subtract(const_1, divide(const_100, add(const_100, 40))), const_100) | add(n0,const_100)|divide(const_100,#0)|subtract(const_1,#1)|multiply(#2,const_100) | general |
jerry travels 8 miles at an average speed of 40 miles per hour , stops for 13 minutes , and then travels another 20 miles at an average speed of 60 miles per hour . what is jerry β s average speed , in miles per hour , for this trip ? | "sol . ( b ) the sum of roots = a + b = 6 product of roots = ab = 6 now , a 2 + b 2 = ( a + b ) 2 - 2 ab = 36 - 12 = 24 answer b" | a ) 36 , b ) 24 , c ) 17 , d ) 6 , e ) 5 | b | add(power(divide(subtract(6, sqrt(subtract(power(6, 2), multiply(const_4, 6)))), 2), 2), power(divide(add(6, sqrt(subtract(power(6, 2), multiply(const_4, 6)))), 2), 2)) | multiply(n1,const_4)|power(n1,n0)|subtract(#1,#0)|sqrt(#2)|add(n1,#3)|subtract(n1,#3)|divide(#5,n0)|divide(#4,n0)|power(#6,n0)|power(#7,n0)|add(#8,#9)| | general |
rhonda picked 2 pen from the table , if there were 7 pens on the table and 5 belongs to jill , what is the probability that the 2 pen she picked does not belong to jill ? . | "let the speed be ' s ' and let the distance between rose and poppy be ' x ' the problem boils down to : rose to poppy : s + 3 = x / 6 - - - - - - - 1 daisy to rose : s = ( x + 3 ) / 10 - - - - - - 2 so from 1 we can re write x as x = 6 s + 18 substitute the value of x in 2 gives us s = 4.2 m / s a" | a ) 4.2 , b ) 5.2 , c ) 6 , d ) 8 , e ) 10 | a | divide(add(multiply(6, 3), 3), 10) | multiply(n1,n3)|add(n2,#0)|divide(#1,n0)| | physics |
if a - b = 3 and a ( power 2 ) + b ( power 2 ) = 23 , find the value of ab . | the fraction is nothing but the probability . . number to choose 3 out of 6 = 6 c 3 number to choose x and y and 2 from remaining 4 = 4 c 2 . . prob of a and b choosen = 4 c 2 / 6 c 3 = 3 / 10 answer : d | a ) 1 / 4 , b ) 1 / 70 , c ) 3 / 14 , d ) 3 / 10 , e ) 11 / 14 | d | divide(factorial(3), multiply(subtract(6, const_1), const_4)) | factorial(n1)|subtract(n0,const_1)|multiply(#1,const_4)|divide(#0,#2) | general |
what is the greater of the two numbers whose product is 2496 , given that the sum of the two numbers exceeds their difference by 64 ? | "explanation : let the average score of the first 18 innings be n 18 n + 94 = 19 ( n + 4 ) = > n = 18 so , average score after 19 th innings = x + 4 = 22 . answer : d" | a ) 28 , b ) 27 , c ) 26 , d ) 22 , e ) 24 | d | add(subtract(94, multiply(19, 4)), 4) | multiply(n1,n2)|subtract(n0,#0)|add(n2,#1)| | general |
the effective annual rate of interest corresponding to a nominal rate of 14 % per annum payable half - yearly is ? | "explanation : present age is 4 x and 2 x , = > 4 x + 22 = 26 = > x = 1 so deepak age is = 2 ( 1 ) = 2 answer : option d" | a ) 9 , b ) 3 , c ) 5 , d ) 2 , e ) 7 | d | divide(multiply(subtract(22, 6), 2), 4) | subtract(n3,n2)|multiply(n1,#0)|divide(#1,n0)| | other |
a recipe requires 2 1 / 2 ( mixed number ) cups of flour 2 3 / 4 ( mixed number ) cups of sugar and 1 1 / 3 ( mixed number ) cups of milk to make one cake . victor has 15 cups if flour , 16 cups of sugar and 8 cups of milk . what is the greatest number of cakes bil can make using this recipe ? | d = 72 * 5 / 18 = 25 = 500 β 150 = 299 . answer : c | a ) 288 , b ) 236 , c ) 350 , d ) 299 , e ) 266 | c | subtract(multiply(25, multiply(72, const_0_2778)), 150) | multiply(n1,const_0_2778)|multiply(n2,#0)|subtract(#1,n0)| | physics |
bag contains 7 green and 8 white balls . if two balls are drawn simultaneously , the probability that both are of the same colour is - . | explanation : bg = ( td ) 2 / pw = 722 / 1296 = 72 Γ 72 / 1296 = 12 Γ 12 / 36 = 12 / 3 = rs . 4 bg = bd β td = > 4 = bd - 72 = > bd = 72 + 4 = rs . 76 answer : option a | a ) rs . 76 , b ) rs . 72 , c ) rs . 74 , d ) rs . 4 , e ) none of these | a | add(72, divide(power(72, const_2), 1296)) | power(n1,const_2)|divide(#0,n0)|add(n1,#1) | gain |
find the sum the difference between the compound and s . i . on a certain sum of money for 2 years at 10 % per annum is rs . 10 of money ? | "let x be the number of students in the class . let p be the average of the rest of the class . 88 x = ( 1 / 3 ) 94 x + ( 2 / 3 ) ( p ) x 264 = 94 + 2 p 2 p = 170 p = 85 . the answer is d ." | a ) 82 , b ) 83 , c ) 84 , d ) 85 , e ) 86 | d | divide(subtract(multiply(88, const_4), 94), subtract(const_4, const_1)) | multiply(n0,const_4)|subtract(const_4,const_1)|subtract(#0,n1)|divide(#2,#1)| | general |
a 125 meter long train crosses a man standing on the platform in 5 sec . what is the speed of the train ? | "explanation : speed of the truck = distance / time = 376 / 8 = 47 kmph now , speed of car = ( speed of truck + 18 ) kmph = ( 47 + 18 ) = 65 kmph distance travelled by car = 376 + 14 = 390 km time taken by car = distance / speed = 390 / 65 = 6 hours . answer β a" | a ) 6 hours , b ) 5 hours , c ) 7 hours , d ) 8 hours , e ) none | a | divide(add(376, 14), add(divide(376, 8), 18)) | add(n0,n3)|divide(n0,n1)|add(n2,#1)|divide(#0,#2)| | physics |
what is the length of the diagonal of a square whose area is 4 times of another square with diagonal as 5 v 2 cm ? | let , maala β s age = 3 a and kala β s age = 5 a then 3 a + 5 a = 32 a = 4 maala β s age = 12 years and kala β s age = 20 years proportion of their ages after 8 is = ( 12 + 8 ) : ( 20 + 8 ) = 20 : 28 = 5 : 7 answer : b | a ) 6 : 5 , b ) 5 : 7 , c ) 4 : 5 , d ) 7 : 9 , e ) 3 : 6 | b | divide(add(multiply(divide(multiply(3.2, 10), add(3, 5)), 3), multiply(0.8, 10)), add(multiply(5, divide(multiply(3.2, 10), add(3, 5))), multiply(0.8, 10))) | add(n0,n1)|multiply(n2,n5)|multiply(n3,n5)|divide(#1,#0)|multiply(n0,#3)|multiply(n1,#3)|add(#4,#2)|add(#5,#2)|divide(#6,#7) | general |
if a * b = 2 a - 3 b + ab , then 3 * 5 + 5 * 3 is equal to : | "the cost of annie ' s ride was 2.5 + 5 + ( 0.25 * 18 ) = $ 12 let x be the distance of mike ' s ride . the cost of mike ' s ride is 2.5 + ( 0.25 * x ) = 12 0.25 * x = 9.5 x = 38 miles the answer is c ." | a ) 30 , b ) 34 , c ) 38 , d ) 42 , e ) 48 | c | divide(subtract(add(add(2.50, 5.00), multiply(0.25, 18)), 2.50), 0.25) | add(n0,n3)|multiply(n1,n5)|add(#0,#1)|subtract(#2,n0)|divide(#3,n1)| | general |
how many positive integers less than 253 are multiple of 4 but not multiples of 6 ? | 1 hr = 20 percent . thus 15 min = 5 percent . now to charge 55 percent 165 min . answer : d | a ) 145 , b ) 150 , c ) 175 , d ) 165 , e ) 130 | d | multiply(divide(55, 20), const_60) | divide(n2,n1)|multiply(#0,const_60)| | physics |
solve below question 2 x + 1 = - 15 | "p ( neither pen is defective ) = 8 / 11 * 7 / 10 = 28 / 55 the answer is a ." | a ) 28 / 55 , b ) 19 / 33 , c ) 7 / 11 , d ) 4 / 7 , e ) 3 / 5 | a | multiply(divide(subtract(11, 3), 11), divide(subtract(subtract(11, 3), const_1), subtract(11, const_1))) | subtract(n0,n1)|subtract(n0,const_1)|divide(#0,n0)|subtract(#0,const_1)|divide(#3,#1)|multiply(#2,#4)| | general |
a train 300 m long , running with a speed of 54 km / hr will pass a tree in ? | "going down = 32 m going up = 16 - - > total = 48 going down = 16 - - > total = 64 going up = 8 - - > total = 72 going down = 8 - - > total = 80 going up = 4 - - > total = 84 going down = 4 - - > total = 86 going up = 2 - - > total = 88 ( caught ) no of bounces = 4 answer : a" | a ) 4 , b ) 6 , c ) 7 , d ) 8 , e ) 9 | a | divide(divide(32, const_2), const_2) | divide(n0,const_2)|divide(#0,const_2)| | general |
village a β s population is 300 greater than village b ' s population . if village b β s population were reduced by 600 people , then village a β s population would be 4 times as large as village b ' s population . what is village b ' s current population ? | "here , drawing a quick sketch of the ' actions ' described will end in a diagonal line that you canbuilda right triangle around : the right triangle will have a base of 90 and a height of 120 . the hidden pattern here is a 3 / 4 / 5 right triangle ( the 90 lines up with the ' 3 ' and the 120 lines up with the ' 4 ' ) . in this way , you can deduce that each side is ' 30 times ' bigger than it ' s corresponding side : 3 / 4 / 5 becomes 90 / 120 / 150 thus the distance between the two cars is the length of the hypotenuse of this larger right triangle . . . final answer : d" | a ) 120 , b ) 130 , c ) 140 , d ) 150 , e ) 160 | d | sqrt(add(power(add(multiply(35, 2), multiply(25, 2)), const_2), power(multiply(35, 2), const_2))) | multiply(n2,n3)|multiply(n1,n3)|add(#0,#1)|power(#0,const_2)|power(#2,const_2)|add(#4,#3)|sqrt(#5)| | physics |
a jogger running at 9 km / hr along side a railway track is 240 m ahead of the engine of a 140 m long train running at 45 km / hr in the same direction . in how much time will the train pass the jogger ? | "explanation : number of blocks = ( 160 x 100 x 60 / 20 x 20 x 20 ) = 120 answer : d" | a ) 30 , b ) 60 , c ) 90 , d ) 120 , e ) 140 | d | volume_rectangular_prism(divide(1.6, divide(20, const_100)), divide(1, divide(20, const_100)), divide(divide(60, const_100), divide(20, const_100))) | divide(n3,const_100)|divide(n2,const_100)|divide(n0,#0)|divide(n1,#0)|divide(#1,#0)|volume_rectangular_prism(#2,#3,#4)| | physics |
the area of a circular field is 17.56 hectares . find the cost of fencing it at the rate of rs . 2 per metre approximately | "if average of 3 is 9 so sum of 3 should be 27 3 recording can be from 0 - 10 inclusive to find one smallest other two should be highest so , lets assume three var are a , b , c say a is smallest and give b and c greatest readings say 10 and 10 so a has to be 7 e" | a ) 2 , b ) 3 , c ) 4 , d ) 5 , e ) 7 | e | subtract(multiply(3, 9), 10) | multiply(n2,n3)|subtract(#0,n1)| | general |
if y > 0 , ( 10 y ) / 20 + ( 3 y ) / 10 is what percent of y ? | if caoacity of q is x units , then capacity of p is 3 x and capacity of drum is 60 * 3 x = 180 x . it will take 180 x / 4 x = 45 turns it will take for both the buckets p & q , having each turn together to fill the empty drum . answer : a | a ) 45 , b ) 53 , c ) 54 , d ) 46 , e ) 63 | a | divide(const_1, add(divide(const_1, 60), divide(const_1, multiply(60, const_3)))) | divide(const_1,n0)|multiply(n0,const_3)|divide(const_1,#1)|add(#0,#2)|divide(const_1,#3) | other |
in a class of 50 students , 20 play baseball , 15 play cricket and 11 play football . 7 play both baseball and cricket , 4 play cricket and football and 5 play baseball and football . if 18 students do not play any of these given sports , how many students play exactly two of these sports ? | "let the son ' s present age be x years . then , ( 40 - x ) = x x = 20 . son ' s age 5 years back = ( 20 - 5 ) = 15 years answer : c" | a ) 14 , b ) 17 , c ) 15 , d ) 19 , e ) 99 | c | subtract(divide(40, const_2), 5) | divide(n0,const_2)|subtract(#0,n1)| | general |
2 cow β s and 5 goats are brought for rs . 1050 . if the average price of a goat be rs . 90 . what is the average price of a cow . | "clearly , the numbers are ( 30 x 13 ) and ( 30 x 14 ) . larger number = ( 30 x 14 ) = 420 . answer : option c" | a ) 276 , b ) 299 , c ) 420 , d ) 345 , e ) 365 | c | multiply(30, 14) | multiply(n0,n2)| | other |
if a train , travelling at a speed of 90 kmph , crosses a pole in 6 sec , then the length of train is ? | "amount = rs [ 7500 * ( 1 + ( 4 / 100 ) 2 ] = rs ( 7500 * ( 26 / 25 ) * ( 26 / 25 ) ) = rs . 8112 . therefore , compound interest = rs . ( 8112 - 7500 ) = rs . 612 . answer is e ." | a ) 812 , b ) 712 , c ) 412 , d ) 512 , e ) 612 | e | subtract(add(add(7500, divide(multiply(7500, 4), const_100)), divide(multiply(add(7500, divide(multiply(7500, 4), const_100)), 4), const_100)), 7500) | multiply(n0,n1)|divide(#0,const_100)|add(n0,#1)|multiply(n1,#2)|divide(#3,const_100)|add(#2,#4)|subtract(#5,n0)| | gain |
a man invests some money partly in 12 % stock at 105 and partly in 8 % stock at 88 . to obtain equal dividends from both , he must invest the money in the ratio : | "m = 5.0 s = 1.5 ds = 6.5 us = 3.5 as = ( 2 * 6 * 3 ) / 10 = 4.55 answer : e" | a ) 7 , b ) 4 , c ) 6 , d ) 9 , e ) 4.55 | e | divide(add(5, subtract(5, 1.5)), const_2) | subtract(n0,n1)|add(n0,#0)|divide(#1,const_2)| | general |
among the two clocks , clock a gains 20 seconds per minute . if clock a and b are set at 2 0 ' clock , when clock a is at 7 : 20 , what does clock b show ? | let the total number of valid votes be x . 70 % of x = 70 / 100 * x = 7 x / 10 number of votes secured by the other candidate = x - 7 x / 100 = 3 x / 10 given , 7 x / 10 - 3 x / 10 = 178 = > 4 x / 10 = 178 = > 4 x = 1780 = > x = 445 . answer : a | a ) 445 , b ) 570 , c ) 480 , d ) 520 , e ) 550 | a | divide(178, divide(subtract(70, subtract(const_100, 70)), const_100)) | subtract(const_100,n0)|subtract(n0,#0)|divide(#1,const_100)|divide(n1,#2) | gain |
a trader sells 40 metres of cloth for rs . 8200 at a profit of rs . 15 per metre of cloth . how much profit will the trder earn on 40 metres of cloth ? | "angle between two hands = 30 h - 11 / 2 m = 30 * 10 - 30 * 11 / 2 = 300 - 165 = 135 deg answer : e" | a ) 65 deg , b ) 75 deg , c ) 45 deg , d ) 15 deg , e ) 135 deg | e | subtract(multiply(30, multiply(const_3, const_2)), 10) | multiply(const_2,const_3)|multiply(n1,#0)|subtract(#1,n0)| | geometry |
the l . c . m . of 2 numbers is 72 . the numbers are in the ratio 2 : 3 . find their sum ? | oa is definitely wrong . the answer should be d . | a ) $ 0.50 , b ) $ 1.00 , c ) $ 1.25 , d ) $ 1.50 , e ) $ 1.75 | d | add(multiply(0.25, subtract(5, 1)), 0.25) | subtract(n1,n0)|multiply(n3,#0)|add(n3,#1)| | general |
two spherical balls lie on the ground touching . if one of the balls has a radius of 8 cm , and the point of contact is 12 cm above the ground , what is the radius of the other ball ( in centimeters ) ? | "this problem can be solved as a simple word problem in which we must convert words to math . before we create our equations , we want to define some variables . j = jake β s current weight , in pounds s = sister β s current weight , in pounds we are told that β if jake loses 8 pounds , he will weigh twice as much as his sister . we put this into an equation : j β 5 = 3 s j = 3 s + 5 ( equation 1 ) next , we are told that β together they now weigh 275 pounds . β we can also put this into an equation . j + s = 285 ( equation 2 ) to solve this equation , we can substitute 2 s + 8 from equation 1 for the variable j in equation 2 : 3 s + 5 = 285 - s 4 s = 280 s = 70 j + 70 = 285 j = 215 answer : e" | a ) 131 , b ) 135 , c ) 139 , d ) 147 , e ) 215 | e | divide(add(multiply(const_2, 285), 5), const_3) | multiply(n1,const_2)|add(n0,#0)|divide(#1,const_3)| | general |
liz drove from point a to point b at 40 km / h . on her way back she drove at 50 km / h and therefore her way back lasted one hour less . what is the distance ( in km ) between a and b ? | explanation : if six computers require 9 days to process the data , thats a total of 54 computer - days the product of 6 and 9 . if you change the number of computers or the number of days , 54 will have to remain the product , whether that means 54 days of one computer or one day with 54 computers . in 6 days , the number of computers is : 6 c = 54 c = 9 9 computers is 3 more than the 6 that it took to do the job in 9 days , so the correct choice is ( a ) . | a ) 3 , b ) 5 , c ) 6 , d ) 9 , e ) 12 | a | subtract(divide(multiply(6, divide(const_1, 6)), divide(const_1, 9)), 6) | divide(const_1,n0)|divide(const_1,n1)|multiply(n0,#0)|divide(#2,#1)|subtract(#3,n0) | physics |
the area of a triangle is with base 5.5 m and height 6 m ? | "r = 7 h = 4 2 Ο r ( h + r ) = 2 * 22 / 7 * 7 ( 11 ) = 484 answer : a" | a ) 484 , b ) 771 , c ) 440 , d ) 767 , e ) 1981 | a | surface_cylinder(7, 4) | surface_cylinder(n0,n1)| | geometry |
gary drove from point a to point b at 60 km / h . on his way back he took a train travelling at 110 km / h and therefore his trip back lasted 5 hours less . what is the distance ( in km ) between a and b ? | "this question can be solved with a handful of different algebra approaches ( as has been shown in the various posts ) . since the question asks for the price of the largest pot , and the answers are prices , we can test the answers . we ' re told that there are 6 pots and that each pot costs 25 cents more than the next . the total price of the pots is $ 8.25 . we ' re asked for the price of the largest ( most expensive ) pot . since the total price is $ 8.00 ( a 25 - cent increment ) and the the difference in sequential prices of the pots is 25 cents , the largest pot probably has a price that is a 25 - cent increment . from the answer choices , i would then test answer c first ( since answers b and d are not in 25 - cent increments ) . if . . . . the largest pot = $ 1.958 0.708 0.958 1.208 1.458 1.708 1.958 total = $ 8.00 so this must be the answer . b" | a ) $ 1.75 , b ) $ 1.96 , c ) $ 2.00 , d ) $ 2.15 , e ) $ 2.30 | b | add(divide(subtract(8.00, multiply(divide(multiply(subtract(6, const_1), 6), const_2), 0.25)), 6), multiply(subtract(6, const_1), 0.25)) | subtract(n0,const_1)|multiply(n0,#0)|multiply(n2,#0)|divide(#1,const_2)|multiply(n2,#3)|subtract(n1,#4)|divide(#5,n0)|add(#6,#2)| | general |
the number of timeshare condos available at sunset beach is 2 / 5 the number of timeshare condos available at playa del mar . if the total number of timeshare condos available at the two beaches combined is 350 , what is the difference between the number of condos available at sunset beach and the number of condos available at playa del mar ? | "solution : both fractions should be reduced before performing arithmetic operations . we get ( 27 / 31 * 31 / 27 ) 3 = 1 * 3 = 3 answer d" | a ) 0 , b ) 1 , c ) 2 , d ) 3 , e ) none | d | divide(add(subtract(add(27, multiply(31, 27)), subtract(3, 27)), const_1), 31) | multiply(n0,n1)|subtract(n4,n3)|add(n3,#0)|subtract(#2,#1)|add(#3,const_1)|divide(#4,n2)| | general |
john bought a shirt on sale for 25 % off the original price and another 25 % off the discounted price . if the final price was $ 14 , what was the price before the first discount ? | "explanation : area of theplot = 110 * 65 = 7150 sq m area of the plot excluding the path = ( 110 - 5 ) * ( 65 - 5 ) = 6300 sq m area of the path = 7150 - 6300 = 850 sq m cost of gravelling the path = 850 * 80 / 100 = 680 rs answer : a ) 680 rs" | a ) 680 , b ) 378 , c ) 267 , d ) 299 , e ) 271 | a | multiply(divide(80, const_100), subtract(multiply(110, 65), multiply(subtract(110, 5), subtract(65, 5)))) | divide(n3,const_100)|multiply(n0,n1)|subtract(n0,n2)|subtract(n1,n2)|multiply(#2,#3)|subtract(#1,#4)|multiply(#0,#5)| | physics |
solution p is 20 percent lemonade and 80 percent carbonated water by volume ; solution q is 45 percent lemonade and 55 percent carbonated water by volume . if a mixture of pq contains 75 percent carbonated water , what percent of the volume of the mixture is p ? | explanation : one bag of husk = 16 cows per day β 16 Γ 1 Γ 16 = 1 Γ 16 Γ x for one cow = 16 days answer : a | a ) 16 , b ) 40 , c ) 20 , d ) 26 , e ) 30 | a | multiply(divide(16, 16), 16) | divide(n0,n0)|multiply(n0,#0) | physics |
a truck covers a distance of 550 metres in 1 minute whereas a train covers a distance of 33 kms in 45 minutes . what is the ratio of their speed ? | explanation : pumps work time 12 1218 99 x 2030 132 = > 1218 / ( 912 * 99 ) = 2020 / ( x Γ 132 ) = > x = 15 pumps answer : option b | a ) 12 , b ) 15 , c ) 18 , d ) 21 , e ) 22 | b | divide(multiply(multiply(multiply(12, 11), 9), 2030), multiply(multiply(12, 11), 1218)) | multiply(n0,n2)|multiply(n3,#0)|multiply(n1,#0)|multiply(n4,#1)|divide(#3,#2) | physics |
a 6 litre sol is 40 % alcohol . how many litres of pure alcohol must be added to produce a sol that is 50 % alcohol ? | "one possible case is : rainy - rainy - rainy - not rainy . the probability of this case is 1 / 5 * 1 / 5 * 1 / 5 * 4 / 5 = 4 / 625 the number of possible cases is 4 c 3 = 4 . p ( exactly 3 rainy days ) = 4 * 4 / 625 = 16 / 625 the answer is e ." | a ) 2 / 25 , b ) 3 / 125 , c ) 7 / 125 , d ) 12 / 625 , e ) 16 / 625 | e | multiply(4, power(divide(const_1, const_2), 4)) | divide(const_1,const_2)|power(#0,n2)|multiply(n2,#1)| | general |
if 625 ( 5 ^ x ) = 1 then x = | "explanation : place value = local value face value = absolute value the place value of 2 in 564823 is 2 x 10 = 20 the face value of 2 in 564823 is nothing but 2 . = > 20 x 2 = 40 answer : option a" | a ) 40 , b ) 60 , c ) 80 , d ) 100 , e ) 18000 | a | multiply(multiply(2, const_1000), 2) | multiply(n0,const_1000)|multiply(n0,#0)| | general |
a trader bought a car at 20 % discount on its original price . he sold it at a 80 % increase on the price he bought it . what percent of profit did he make on the original price ? | "explanation : solution : the required population is 60000 ( 1 + 10 / 100 ) ^ 3 = 60000 * 110 / 100 * 110 / 100 * 110 / 100 = 79,860 answer : b" | a ) 86000 , b ) 79860 , c ) 76300 , d ) 82900 , e ) none of these | b | add(60,000, divide(multiply(60,000, 10), const_100)) | multiply(n0,n1)|divide(#0,const_100)|add(n0,#1)| | gain |
the difference between the place value and the face value of 5 in the numeral 856973 is | "25.25 / 2000 = 2525 / 200000 = 0.01616 answer : d" | a ) 1.012526 , b ) 0.012625 , c ) 0.12526 , d ) 0.01616 , e ) 0.12725 | d | divide(32.32, 2000) | divide(n0,n1)| | general |
if 6 - 12 / x = 7 - 7 / x , then x = | let the amount of money be 200 let cost of 1 orange be 4 let cost of 1 mango be 5 he decides to retain 5 % of 200 = 10 for taxi fare , so he is left with 190 he buys 20 mangoes ( @ 5 ) so he spends 100 money left is 90 ( 190 - 100 ) no of oranges he can buy = 90 / 4 = > 22,5 so , george can buy 20 oranges . d | a ) 25 , b ) 30 , c ) 20 , d ) 22.5 , e ) 12 | d | multiply(subtract(subtract(const_1, divide(5, const_100)), divide(25, 50)), 50) | divide(n2,const_100)|divide(n3,n0)|subtract(const_1,#0)|subtract(#2,#1)|multiply(n0,#3) | general |
a is 1.5 times as fast as b . a alone can do the work in 20 days . if a and b working together , in how many days will the work be completed ? | "explanation : let the required number days be x . less spiders , more days ( indirect proportion ) less webs , less days ( direct proportion ) spiders 1 : 4 | | : : 4 : 1 webs 4 : 1 | = > 1 * 4 * x = 4 * 1 * 4 = > x = 4 answer : d" | a ) 1 , b ) 3 , c ) 5 , d ) 4 , e ) 6 | d | multiply(1, 4) | multiply(n0,n3)| | physics |
carl is facing very difficult financial times and can only pay the interest on a $ 30,000 loan he has taken . the bank charges him a quarterly compound rate of 5 % . what is the approximate interest he pays annually ? | "girls = 900 , boys = 1100 passed = ( 36 % of 1100 ) + ( 32 % of 900 ) = 396 + 288 = 684 failed = 2000 - 684 = 1316 failed % = [ ( 1316 / 2000 ) x 100 ] % = 65.8 % . answer : b" | a ) 35.67 % , b ) 65.80 % , c ) 68.57 % , d ) 69.57 % , e ) none of these | b | multiply(divide(subtract(subtract(multiply(const_2, multiply(const_100, const_10)), multiply(divide(36, const_100), subtract(multiply(const_2, multiply(const_100, const_10)), 900))), multiply(divide(32, const_100), 900)), multiply(const_2, multiply(const_100, const_10))), const_100) | divide(n2,const_100)|divide(n3,const_100)|multiply(const_10,const_100)|multiply(#2,const_2)|multiply(n1,#1)|subtract(#3,n1)|multiply(#0,#5)|subtract(#3,#6)|subtract(#7,#4)|divide(#8,#3)|multiply(#9,const_100)| | general |
find the length of the wire required to go 14 times round a square field containing 5625 m 2 . | "the total distance d traveled by john is given by d = 50 * 2 + 3 * 55 = 265 miles . answer d" | a ) 235 miles . , b ) 245 miles . , c ) 255 miles . , d ) 265 miles . , e ) 275 miles . | d | add(multiply(50, 2), multiply(3, 55)) | multiply(n0,n1)|multiply(n2,n3)|add(#0,#1)| | physics |
the radius of a wheel is 20 cm . what is the distance covered by the wheel in making 500 resolutions ? | "volume of water displaced = ( 3 x 2 x 0.01 ) m 3 = 0.06 m 3 . mass of man = volume of water displaced x density of water = ( 0.06 x 1000 ) kg = 60 kg . answer : option b" | a ) 12 kg , b ) 60 kg , c ) 72 kg , d ) 88 kg , e ) 96 kg | b | multiply(multiply(multiply(3, 2), divide(1, const_100)), const_1000) | divide(n2,const_100)|multiply(n0,n1)|multiply(#0,#1)|multiply(#2,const_1000)| | physics |
the ratio of 2 numbers is 2 : 8 and their h . c . f . is 40 . their l . c . m . is ? | base of triangle is 20 and area is 80 therefore height = 2 * 80 / 20 = 8 . now one side of triangle is of 10 . so we can get the point were the base is divided by applying pythagoras therm so division pt = sqrt ( 10 ^ 2 - 8 ^ 2 ) = sqrt ( 36 ) = 6 threfore other half is 14 . now second side = sqrt ( 14 ^ 2 + 8 ^ 2 ) = sqrt ( 260 ) = 2 sqrt ( 65 ) answer : e | ['a ) 2 sqrt ( 61 )', 'b ) 2 sqrt ( 62 )', 'c ) 2 sqrt ( 63 )', 'd ) 2 sqrt ( 64 )', 'e ) 2 sqrt ( 65 )'] | e | sqrt(add(power(divide(multiply(80, const_2), 20), const_2), power(subtract(20, sqrt(subtract(power(10, const_2), power(divide(multiply(80, const_2), 20), const_2)))), const_2))) | multiply(n2,const_2)|power(n1,const_2)|divide(#0,n0)|power(#2,const_2)|subtract(#1,#3)|sqrt(#4)|subtract(n0,#5)|power(#6,const_2)|add(#3,#7)|sqrt(#8) | geometry |
107 x 107 + 93 x 93 = ? | 5 x $ 3 = $ 15 for baby - sitting 3 x $ 4 = $ 12 for garden work $ 15 + $ 12 = $ 27 she has $ 35 - $ 27 = $ 8 more needed to buy the game correct answer a | a ) $ 8 , b ) $ 12 , c ) $ 6 , d ) $ 21 , e ) $ 10 | a | subtract(35, add(multiply(5, 3), multiply(3, 4))) | multiply(n0,n2)|multiply(n0,n1)|add(#0,#1)|subtract(n4,#2) | general |
two pipes a and b can separately fill a tank in 10 and 15 minutes respectively . a third pipe c can drain off 20 liters of water per minute . if all the pipes are opened , the tank can be filled in 15 minutes . what is the capacity of the tank ? | "the arithmetic mean of a and b = ( a + b ) / 2 = 45 - - a + b = 90 - - 1 similarly for b + c = 160 - - 2 subtracting 1 from 2 we have c - a = 70 ; answer : b" | a ) 25 , b ) 70 , c ) 90 , d ) 140 , e ) it can not be determined from the information given | b | subtract(multiply(80, const_2), multiply(45, const_2)) | multiply(n1,const_2)|multiply(n0,const_2)|subtract(#0,#1)| | general |
dan can do a job alone in 15 hours . annie , working alone , can do the same job in just 10 hours . if dan works alone for 12 hours and then stops , how many hours will it take annie , working alone , to complete the job ? | "800 * 8.2 6560.0 gm 6.56 kg answer : a" | a ) 6.56 kg , b ) 6.8 kg , c ) 6.7 kg , d ) 6.9 kg , e ) 7.8 kg | a | divide(multiply(8.2, 800), const_1000) | multiply(n0,n1)|divide(#0,const_1000)| | general |
how many cubes of 5 cm edge can be cut out of a cube of 20 cm edge | ( 1 / 2 ) * ( 1 / 2 ) * ( 1 / 2 ) * ( 1 / 2 ) * ( 1 / 2 ) = 1 / 32 answer : b | a ) 1 / 8 , b ) 1 / 32 , c ) 1 / 4 , d ) 1 / 2 , e ) 1 / 16 | b | divide(const_1, power(2, 5)) | power(n1,n2)|divide(const_1,#0) | probability |
if 9 a - b = 10 b + 70 = - 12 b - 2 a , what is the value of 9 a - 11 b ? | "1 / 2 * d * ( 14 + 8 ) = 990 d = 90 the answer is e ." | a ) 50 , b ) 60 , c ) 70 , d ) 80 , e ) 90 | e | divide(990, divide(add(14, 8), const_2)) | add(n0,n1)|divide(#0,const_2)|divide(n2,#1)| | physics |
cost is expressed by the formula tb ^ 4 . if b is doubled , the new cost q is what percent of the original cost ? | "let the income and the expenditure of the person be rs . 5 x and rs . 4 x respectively . income , 5 x = 14000 = > x = 2800 savings = income - expenditure = 5 x - 4 x = x so , savings = rs . 2800 . answer : b" | a ) 3600 , b ) 2800 , c ) 3608 , d ) 3602 , e ) 3603 | b | subtract(14000, multiply(divide(4, 5), 14000)) | divide(n1,n0)|multiply(n2,#0)|subtract(n2,#1)| | other |
what is the tens digit of 36 ^ 5 ? | "let the amount paid to x per week = x and the amount paid to y per week = y then x + y = 750 but x = 120 % of y = 120 y / 100 = 12 y / 10 β΄ 12 y / 10 + y = 750 β y [ 12 / 10 + 1 ] = 750 β 22 y / 10 = 750 β 22 y = 7500 β y = 7500 / 22 = rs . 340.90 e )" | a ) s . 200.90 , b ) s . 250.90 , c ) s . 290.90 , d ) s . 300.90 , e ) s . 340.90 | e | divide(multiply(750, multiply(add(const_1, const_4), const_2)), multiply(add(multiply(add(const_1, const_4), const_2), const_1), const_2)) | add(const_1,const_4)|multiply(#0,const_2)|add(#1,const_1)|multiply(n0,#1)|multiply(#2,const_2)|divide(#3,#4)| | general |
a train passes a station platform in 34 sec and a man standing on the platform in 20 sec . if the speed of the train is 54 km / hr . what is the length of the platform ? | "sol . ( d ) let the sum be 100 . therefore , si = 100 Γ 5 Γ 2100 = 10100 Γ 5 Γ 2100 = 10 and ci = 100 ( 1 + 5100 ) 2 β 100100 ( 1 + 5100 ) 2 β 100 β΄ = 100 Γ 21 Γ 2120 Γ 20 β 100 = 414 = 100 Γ 21 Γ 2120 Γ 20 β 100 = 414 difference of ci and si = 41 β 4 - 10 = 1 β 4 if the difference is 1 β 4 , the sum = 100 = > if the difference is 19 , the sum = 400 Γ 19 = 7600 answer b" | a ) 4500 , b ) 7600 , c ) 5000 , d ) 6000 , e ) none of these | b | divide(19, subtract(power(add(const_1, divide(5, const_100)), 2), add(const_1, multiply(2, divide(5, const_100))))) | divide(n0,const_100)|add(#0,const_1)|multiply(n1,#0)|add(#2,const_1)|power(#1,n1)|subtract(#4,#3)|divide(n2,#5)| | gain |
there are 400 employees in a room . 99 % are managers . how many managers must leave the room to bring down the percentage of managers to 98 % ? | "explanation : 1398 x 1398 = ( 1398 ) 2 = ( 1400 - 2 ) 2 = 14002 - ( 2 Γ 1400 Γ 2 ) + 22 = 1960000 - 5600 + 4 = 1954404 . answer : option d" | a ) 1624404 , b ) 1851404 , c ) 1951404 , d ) 1954404 , e ) none of these | d | multiply(divide(1398, 1398), const_100) | divide(n0,n1)|multiply(#0,const_100)| | general |
the average height of 20 students in a class was calculated as 175 cm . it has later found that the height of one of the students in the class was incorrectly written as 151 cm whereas the actual height was 131 cm . what was the actual average height of the students in the class ? | "machine b produces 100 part in 60 minutes . machine a produces 100 parts twice as fast as b , so machine a produces 100 parts in 60 / 2 = 30 minutes . now , machine a produces 100 parts in 30 minutes which is 100 / 30 = 10 / 3 parts / minute . 10 / 3 parts x a total of 6 minutes = 20 a" | a ) 20 , b ) 30 , c ) 40 , d ) 10 , e ) 16 | a | multiply(multiply(divide(100, 60), const_2), 6) | divide(n0,n2)|multiply(#0,const_2)|multiply(n3,#1)| | gain |
the general hospital is comprised of , 3 / 5 pediatricians , 1 / 4 surgeons , and the rest are gp doctors . if 1 / 4 of the surgeons are heart surgeons , and the hospital doubles the number of gp doctors , what proportion of the hospital are now heart surgeons ? | "let length of rectangle = l 3 ^ 2 = l * 4 = > l = 9 / 4 = 3 answer d" | a ) 4 , b ) 8 , c ) 12 , d ) 3 , e ) 18 | d | divide(power(3, const_2), 4) | power(n0,const_2)|divide(#0,n1)| | geometry |
a hostel had provisions for 250 men for 44 days . if 50 men left the hostel , how long will the food last at the same rate ? | there are several algebraic ways to solve this question , but the easiest way is as follows : since we can not have two correct answers just pick a prime greater than 5 , square it and see what would be the remainder upon division of it by 12 . n = 7 - - > n ^ 2 = 49 - - > remainder upon division 49 by 12 is 1 . answer : b . | a ) 0 , b ) 1 , c ) 2 , d ) 3 , e ) 5 | b | subtract(power(add(5, const_2), 2), multiply(12, const_4)) | add(n0,const_2)|multiply(n2,const_4)|power(#0,n1)|subtract(#2,#1) | general |
a can finish a work in 36 days , b in 9 days and c in 2 days , b and c start the work but are forced to leave after 3 days . the remaining work was done by a in ? | since there are only 5 integers , another approach is the just list all 5 . we get : - 2 , 0,2 , 4 , 6 range of positive integers = 6 - 2 = 4 answer : c | a ) 0 , b ) 2 , c ) 4 , d ) 6 , e ) 8 | c | subtract(add(negate(2), multiply(subtract(5, const_1), 2)), 2) | negate(n1)|subtract(n0,const_1)|multiply(n1,#1)|add(#2,#0)|subtract(#3,n1) | general |
last year the range of the annual bonus of the 100 employees at company x was $ 20000 . if the annual bonus of each of the 100 employees this year is 10 percent greater than it was last year , what is the range of the annual bonus of the 100 employees this year ? | "36 = 3 ^ 2 * 2 ^ 2 . 36 ^ 450 = 3 ^ 900 * 2 ^ 900 the answer is e ." | a ) 100 , b ) 200 , c ) 300 , d ) 600 , e ) 900 | e | multiply(subtract(36, 450), 450) | subtract(n1,n2)|multiply(n2,#0)| | other |
when x is multiplied by 3 , the result is 18 more than the result of subtracting x from 70 . what is the value of x ? | "easy one - - 25 , - 24 , - 23 , - 22 , . . . . . . - 1,0 , 1 , 2 . . . . , 22 , 23 cancel everyhitng and we ' re left with - - 25 and - 24 g = - 49 . d is the answer ." | a ) 0 , b ) - 2 , c ) - 25 , d ) - 49 , e ) - 51 | d | add(add(negate(26), const_1), add(add(negate(26), const_1), const_1)) | negate(n0)|add(#0,const_1)|add(#1,const_1)|add(#1,#2)| | general |
find the ratio in which rice at rs . 7.20 a kg be mixed with rice at rs . 5.70 a kg to produce a mixture worth rs . 6.30 a kg ? | "c $ 590 s . i . for 1 year = $ ( 710 - 680 ) = $ 30 . s . i . for 3 years = $ ( 30 x 3 ) = $ 90 . principal = $ ( 680 - 90 ) = $ 590 ." | a ) $ 153 , b ) $ 698 , c ) $ 590 , d ) $ 549 , e ) $ 675 | c | subtract(680, divide(multiply(subtract(710, 680), 3), 4)) | subtract(n2,n0)|multiply(n1,#0)|divide(#1,n3)|subtract(n0,#2)| | gain |
a person ' s present age is one - fifth of the age of his mother . after 8 years , he will be one - half of the age of his mother . how old is the mother at present ? | "solution : let x be the number he chose , then 2 * x * 180 = 104 2 x = 284 x = 142 correct answer d" | a ) 90 , b ) 100 , c ) 120 , d ) 142 , e ) 200 | d | divide(add(104, 180), 2) | add(n1,n2)|divide(#0,n0)| | general |
1 / 0.05 is equal to | solution let us name the brothers as a and b . = ( a ' s speed ) : ( b ' s speed ) = Γ’ Λ Ε‘ b : Γ’ Λ Ε‘ a = Γ’ Λ Ε‘ 25 : Γ’ Λ Ε‘ 36 = 5 : 6 answer d | a ) 4 : 5 , b ) 1 : 2 , c ) 6 : 7 , d ) 5 : 6 , e ) none | d | divide(sqrt(25), sqrt(36)) | sqrt(n0)|sqrt(n1)|divide(#0,#1) | physics |
a sum of rs . 1360 has been divided among a , b and c such that a gets 2 / 3 of what b gets and b gets 1 / 4 of what c gets . b ' s share is : | "number of stops in an hour : 60 / 5 = 12 distance between stops : 60 / 12 = 5 km distance between yahya ' s house and pinedale mall : 5 x 9 = 45 km imo , correct answer is ` ` c . ' '" | a ) 20 km , b ) 30 km , c ) 45 km , d ) 50 km , e ) 60 km | c | multiply(60, divide(multiply(5, 9), 60)) | multiply(n1,n2)|divide(#0,n0)|multiply(n0,#1)| | physics |
s = { 12 , 35 , 69 } t = { 45 , 67 , 13 } what is the probability that x chosen from s and y chosen from t will result x * y = even | "if 80 % of the packages weigh at least 25 pounds this means that 20 % of the packages weigh less than 25 pounds let t = total number of packages so , 20 % of t = # of packages that weigh less than 25 pounds 48 packages weigh less than 25 pounds great . so , 20 % of t = 48 rewrite to get : 0.2 t = 48 solve : t = 240 50 % of the packages weigh less than 75 pounds so , 50 % oft = number of packages that weigh less than 75 pounds 50 % of 240 = 120 , so 120 packages weigh less than 75 pounds of those 120 packages that weigh less than 75 pounds , 48 packages weigh less than 25 pounds . so , the number of packages that weight between 25 and 75 pounds = 120 - 48 = 72 = c" | a ) 8 , b ) 64 , c ) 72 , d ) 102 , e ) 144 | c | subtract(divide(multiply(multiply(divide(48, subtract(const_100, 80)), const_100), 50), const_100), 48) | subtract(const_100,n4)|divide(n2,#0)|multiply(#1,const_100)|multiply(n0,#2)|divide(#3,const_100)|subtract(#4,n2)| | general |
in the standard formulation of a flavored drink the ratio by volume of flavoring to corn syrup to water is 1 : 12 : 30 . in the ` ` sport ' ' formulation , the ratio of flavoring to corn syrup is three times as great as in the standard formulation , and the ratio of flavoring to water is half that of the standard formulation . if a large bottle of the ` ` sport ' ' formulation contains 3 ounces of corn syrup , how many ounces of water does it contain ? | "solution speed in still water = 1 / 2 ( 11 + 5 ) kmph . = 8 kmph . answer c" | a ) 3 , b ) 5 , c ) 8 , d ) 9 , e ) 10 | c | divide(add(11, 5), const_2) | add(n0,n1)|divide(#0,const_2)| | physics |
an urn contains 6 red , 5 blue and 2 green marbles . if 2 marbles are picked at random , what is the probability that both are red ? | "let c . p . = rs . 4 x . then , s . p . = rs . 5 x gain = ( 5 x - 4 x ) = rs . x gain % = ( x * 100 ) / 4 x = 25 % . answer : c" | a ) 17 , b ) 56 , c ) 25 , d ) 28 , e ) 12 | c | multiply(subtract(divide(5, 4), const_1), const_100) | divide(n1,n0)|subtract(#0,const_1)|multiply(#1,const_100)| | gain |
there are 13 clubs in a full deck of 52 cards . in a certain game , you pick a card from a standard deck of 52 cards . if the card is a club , you win . if the card is not a club , the person replaces the card to the deck , reshuffles , and draws again . the person keeps repeating that process until he picks a club , and the point is to measure how many draws it took before the person picked a club and , thereby , won . what is the probability that one will pick the first club on the forth draw or later ? | "this question is a weighted average question with a series of dependent variables . the remaining portion of the class represents 100 % - 45 % - 50 % = 5 % of the class converting the portions of the class population to decimal weights , we find : class average = 0.45 x 100 + 0.50 x 78 + 0.05 x 63 = 87.15 the class average ( rounded ) is 87 % final answer b ) 87 %" | a ) 86 % , b ) 87 % , c ) 88 % , d ) 89 % , e ) 90 % | b | divide(add(add(multiply(45, 100), multiply(50, 78)), multiply(subtract(const_100, add(45, 50)), 65)), const_100) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|subtract(const_100,#0)|multiply(n4,#4)|add(#3,#5)|divide(#6,const_100)| | gain |
light glows for every 15 seconds . how many max . times did it glow between 1 : 57 : 58 and 3 : 20 : 47 am . | let x be the total number of votes cast . 0.6 x = 0.4 x + 62 0.2 x = 62 x = 310 the answer is d . | a ) 280 , b ) 290 , c ) 300 , d ) 310 , e ) 320 | d | divide(62, subtract(subtract(const_1, divide(40, const_100)), divide(40, const_100))) | divide(n1,const_100)|subtract(const_1,#0)|subtract(#1,#0)|divide(n0,#2) | gain |
2 cow β s and 5 goats are brought for rs . 1050 . if the average price of a goat be rs . 90 . what is the average price of a cow . | "number start between 20 to 80 is 60 numbers half of them is even . . which is 30 answer : b" | a ) 21 , b ) 30 , c ) 11 , d ) 10 , e ) 9 | b | divide(subtract(80, 20), const_2) | subtract(n1,n0)|divide(#0,const_2)| | general |
if a * b = 2 a - 3 b + ab , then 3 * 5 + 5 * 3 is equal to : | if b is 2 , 4 , 5 , or 10 , then gcd of a and b is 2 , 4 , 5 , and 10 respectively . so , by poe the answer must be d . still : if b is a multiple of 6 , then a is 20 greater than a multiple of 6 , so not a multiple of 6 , so both of them can not be divisive by 6 . answer : d . | a ) 2 , b ) 4 , c ) 5 , d ) 6 , e ) 10 | d | add(divide(20, 5), const_2) | divide(n1,n0)|add(#0,const_2) | general |
a merchant sells an item at a 20 % discount , but still makes a gross profit of 20 percent of the cost . what percent w of the cost would the gross profit on the item have been if it had been sold without the discount ? | "ans : a let x = 44444444 ( x + 1 ) Γ ( 2 x β 3 ) Γ ( x β 2 ) + ( x β 6 ) x 2 ( x + 1 ) Γ ( 2 x β 3 ) Γ ( x β 2 ) + ( x β 6 ) x 2 ( x 2 β x β 2 ) Γ ( 2 x β 3 ) + ( x β 6 ) x 2 ( x 2 β x β 2 ) Γ ( 2 x β 3 ) + ( x β 6 ) x 2 2 x 3 β 2 x 2 β 4 x β 3 x 2 + 3 x + 6 + x β 6 x 22 x 3 β 2 x 2 β 4 x β 3 x 2 + 3 x + 6 + x β 6 x 2 2 x 3 β 5 x 2 x 2 = 2 x β 52 x 3 β 5 x 2 x 2 = 2 x β 5 substituting the value of x in 2 x - 5 , we get 88888883 answer : a" | a ) 88888883 , b ) 88888827 , c ) 16992677 , d ) 88888237 , e ) 88888182 | a | power(44444445, negate(88888885)) | negate(n1)|power(n0,#0)| | general |
find the area of trapezium whose parallel sides are 20 cm and 18 cm long , and the distance between them is 30 cm ? | "105 - 57 = 48 57 - 21 = 36 105 - 21 = 84 the h . c . f of 36 , 48 and 84 is 12 . answer : c" | a ) 18 , b ) 8 , c ) 12 , d ) 16 , e ) none of these | c | divide(subtract(57, 21), const_2) | subtract(n1,n0)|divide(#0,const_2)| | general |
kathleen can paint a room in 2 hours , and anthony can paint an identical room in 7 hours . how many hours would it take kathleen and anthony to paint both rooms if they work together at their respective rates ? | "total - 2100 participants campers are aged 8 to 12 = ( 1 / 2 ) * 2100 = 1050 next year , campers are aged 8 to 12 = ( 4 / 3 ) * 1050 = 1400 percentage = ( 1400 / 2100 ) * 100 = 66 2 / 3 % answer : option e" | a ) 62 , b ) 68 , c ) 66 , d ) 64 , e ) 66 2 / 3 | e | add(multiply(multiply(divide(multiply(divide(add(const_1000, multiply(8, const_100)), 2), add(divide(1, 3), 1)), add(const_1000, multiply(8, const_100))), const_100), 3), divide(multiply(multiply(divide(multiply(divide(add(const_1000, multiply(8, const_100)), 2), add(divide(1, 3), 1)), add(const_1000, multiply(8, const_100))), const_100), 3), const_10)) | divide(n1,n8)|multiply(n3,const_100)|add(#0,n1)|add(#1,const_1000)|divide(#3,n2)|multiply(#2,#4)|divide(#5,#3)|multiply(#6,const_100)|multiply(#7,n8)|divide(#8,const_10)|add(#9,#8)| | general |
find the value of ( 950 + 220 / 900 ) Γ 900 | "35 * 18 / 5 = 126 kmph answer : c" | a ) 122 , b ) 188 , c ) 126 , d ) 140 , e ) 124 | c | multiply(divide(35, const_1000), const_3600) | divide(n0,const_1000)|multiply(#0,const_3600)| | physics |
out of 400 students of a school , 325 play football , 175 play cricket and 50 neither play football nor cricket . how many students play both football and cricket ? | "a 2 = 3136 = > a = 56 56 * 4 * 3 = 672 β 6 = 666 * 2.5 = 1665 answer : d" | a ) s . 1014 , b ) s . 1140 , c ) s . 999 , d ) s . 1665 , e ) s . 1020 | d | multiply(multiply(subtract(multiply(sqrt(3136), const_4), multiply(const_2, 1)), 2.50), 3) | multiply(n3,const_2)|sqrt(n0)|multiply(#1,const_4)|subtract(#2,#0)|multiply(n2,#3)|multiply(#4,n1)| | physics |
what is the next number : 2 , 10 , 82 , __ | "first , let ' s graph the lines y = 4 and x = 2 at this point , we need to find the points where the line y = 6 - 2 x intersects the other two lines . for the vertical line , we know that x = 2 , so we ' ll plug x = 2 into the equation y = 6 - 2 x to get y = 6 - 2 ( 2 ) = 2 perfect , when x = 2 , y = 2 , so one point of intersection is ( 2,2 ) for the horizontal line , we know that y = 4 , so we ' ll plug y = 4 into the equation y = 6 - 2 x to get 4 = 6 - 2 x . solve to get : x = 1 so , when y = 4 , x = 1 , so one point of intersection is ( 1,4 ) now add these points to our graph and sketch the line y = 6 - 2 x at this point , we can see that we have the following triangle . the base has length 1 and the height is 2 area = ( 1 / 2 ) ( base ) ( height ) = ( 1 / 2 ) ( 1 ) ( 2 ) = 1 answer : a" | a ) a ) 1 , b ) b ) 2 , c ) c ) 4 , d ) d ) 6 , e ) e ) 8 | a | multiply(subtract(subtract(6, 4), 4), multiply(multiply(4, const_0_25), subtract(subtract(6, 4), 4))) | multiply(const_0_25,n0)|subtract(n2,n0)|subtract(#1,n0)|multiply(#0,#2)|multiply(#3,#2)| | general |
a constructor estimates that 10 people can paint mr khans house in 4 days . if he uses 5 people instead of 10 , how long will they take to complete the job ? | female = x male = 690 - x x / 2 + 690 - x / 4 = 1 / 3 * ( 690 ) = 230 x = 230 x / 2 = 115 is supposed to be the answer m is missing something correct option c | a ) 75 , b ) 100 , c ) 115 , d ) 175 , e ) 225 | c | divide(subtract(multiply(divide(690, const_3), const_4), 690), const_2) | divide(n0,const_3)|multiply(#0,const_4)|subtract(#1,n0)|divide(#2,const_2) | general |
train a leaves the station traveling at 30 miles per hour . two hours later train Π² leaves the same station traveling in the same direction at 35 miles per hour . how many miles from the station was train a overtaken by train b ? | "area of a parallelogram = base * height = 20 * 40 = 800 cm 2 answer : c" | a ) 100 cm 2 , b ) 250 cm 2 , c ) 800 cm 2 , d ) 296 cm 2 , e ) 456 cm 2 | c | multiply(20, 40) | multiply(n0,n1)| | geometry |
two bullet trains of equal lengths take 10 seconds and 30 seconds respectively to cross a telegraph post . if the length of each bullet train be 120 metres , in what time ( in seconds ) will they cross each other travelling in opposite direction ? | "explanation : each row contains 14 plants . there are 13 gapes between the two corner trees ( 13 x 2 ) metres and 1 metre on each side is left . therefore length = ( 26 + 2 ) m = 28 m . answer : e" | a ) 20 m , b ) 22 m , c ) 24 m , d ) 26 m , e ) 28 m | e | add(add(multiply(subtract(14, const_1), 2), divide(10, 2)), divide(10, 2)) | divide(n0,n2)|subtract(n1,const_1)|multiply(n2,#1)|add(#0,#2)|add(#3,#0)| | physics |
what is the characteristic of the logarithm of 0.0000134 ? | "a ' s 1 hour work = 1 / 6 ; ( b + c ) ' s 1 hour work = 1 / 4 ; ( a + c ) ' s 1 hour work = 1 / 3 ( a + b + c ) ' s 1 hour work = ( 1 / 4 + 1 / 6 ) = 5 / 12 b ' s 1 hour work = ( 5 / 12 - 1 / 3 ) = 1 / 12 b alone will take 12 hours to do the work . answer : d" | a ) 8 hours , b ) 6 hours , c ) 14 hours , d ) 12 hours , e ) 5 hours | d | divide(const_1, subtract(divide(const_1, 4), subtract(divide(const_1, 3), divide(const_1, 6)))) | divide(const_1,n1)|divide(const_1,n2)|divide(const_1,n0)|subtract(#1,#2)|subtract(#0,#3)|divide(const_1,#4)| | physics |
( 0.0066 ) ( 3.6 ) / ( 0.04 ) ( 0.1 ) ( 0.006 ) = | "d = 72 * 5 / 18 = 30 = 600 Γ’ β¬ β 250 = 350 m answer : a" | a ) 350 m , b ) 200 m , c ) 250 m , d ) 270 m , e ) 300 m | a | subtract(multiply(30, multiply(72, const_0_2778)), 250) | multiply(n1,const_0_2778)|multiply(n2,#0)|subtract(#1,n0)| | physics |
if a and b are positive integers , and a = 5 b + 20 , the greatest common divisor of a and b can not be | akar has = ram + rahul + john after evenly distribution each has 11 . so , total no . is 44 so , akar has = 22 & ram + rahul + john = 22 also ram = rahul - 4 & john - 3 = 3 * ram solving these we get the sol . answer : b | a ) 2 , b ) 3 , c ) 4 , d ) 5 , e ) 6 | b | divide(subtract(multiply(11, const_2), add(4, 3)), add(4, const_1)) | add(n0,n1)|add(n0,const_1)|multiply(n4,const_2)|subtract(#2,#0)|divide(#3,#1) | general |