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bird-iql

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superhero

Give the race of the blue-haired male superhero.

blue-haired refers to colour.colour = 'blue' WHERE hair_colour_id = colour.id; male refers to gender = 'male';

SELECT T3.race FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.hair_colour_id = T2.id INNER JOIN race AS T3 ON T1.race_id = T3.id INNER JOIN gender AS T4 ON T1.gender_id = T4.id WHERE T2.colour = 'Blue' AND T4.gender = 'Male'

SuperheroView

filter_by_gender("Male") AND filter_by_hair_colour("Blue")

moderate

superhero

Among the bad superheroes, what is the percentage of female superheroes?

bad superheroes refers to alignment.id = 2; percentage = MULTIPLY(DIVIDE(SUM(gender.id = 2 WHERE alignment.id = 2), COUNT(alignment.id = 2)), 100.0); female refers to gender.id = 2;

SELECT CAST(COUNT(CASE WHEN T3.gender = 'Female' THEN T1.id ELSE NULL END) AS REAL) * 100 / COUNT(T1.id) FROM superhero AS T1 INNER JOIN alignment AS T2 ON T1.alignment_id = T2.id INNER JOIN gender AS T3 ON T1.gender_id = T3.id WHERE T2.alignment = 'Bad'

SuperheroView

filter_by_alignment("Bad")

percentage_of_gender("Female")

challenging

superhero

In superheroes with missing weight data, calculate the difference between the number of superheroes with blue eyes and no eye color.

missing weight data refers to weight_kg = 0 OR T1.weight_kg = NULL; difference = SUBTRACT(SUM(colour.id = 7), SUM(colour.id = 1)); blue eyes refers to eye_colour_id WHERE colour.id = 7; no eye color refers to eye_colour_id WHERE colour.id = 1;

SELECT SUM(CASE WHEN T2.id = 7 THEN 1 ELSE 0 END) - SUM(CASE WHEN T2.id = 1 THEN 1 ELSE 0 END) FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T1.weight_kg = 0 OR T1.weight_kg is NULL

SuperheroView

filter_by_missing_weight()

challenging

superhero

How strong is the Hulk?

how strong refers to attribute_value WHERE attribute_name = 'Strength'; the Hulk refers to superhero_name = 'Hulk';

SELECT T2.attribute_value FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id INNER JOIN attribute AS T3 ON T2.attribute_id = T3.id WHERE T1.superhero_name = 'Hulk' AND T3.attribute_name = 'Strength'

moderate

superhero

List down Ajax's superpowers.

Ajax refers to superhero_name = 'Ajax'; superpowers refers to power_name;

SELECT T3.power_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T1.superhero_name = 'Ajax'

simple

superhero

How many green-skinned villains are there in the superhero universe?

green-skinned refers to colour.colour = 'Green' WHERE skin_colour_id = colour.id; villains refers to alignment = 'Bad';

SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN alignment AS T2 ON T1.alignment_id = T2.id INNER JOIN colour AS T3 ON T1.skin_colour_id = T3.id WHERE T2.alignment = 'Bad' AND T3.colour = 'Green'

SuperheroView

filter_by_alignment("Bad") AND filter_by_skin_colour("Green")

count_superheroes()

moderate

superhero

How many female superheroes are in Marvel Comics?

female refers to gender = 'Female'; Marvel Comics refers to publisher_name = 'Marvel Comics';

SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN gender AS T3 ON T1.gender_id = T3.id WHERE T2.publisher_name = 'Marvel Comics' AND T3.gender = 'Female'

SuperheroView

filter_by_publisher_name("Marvel Comics") AND filter_by_gender("Female")

count_superheroes()

moderate

superhero

Identify superheroes who can control wind and list their names in alphabetical order.

superheroes refers to superhero_name; can control wind refers to power_name = 'Wind Control';

SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T3.power_name = 'Wind Control' ORDER BY T1.superhero_name

SuperheroView

moderate

superhero

Identify the gender of the superhero who has the ability of Phoenix Force.

ability of Phoenix Force refers to power_name = 'Phoenix Force';

SELECT T4.gender FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id INNER JOIN gender AS T4 ON T1.gender_id = T4.id WHERE T3.power_name = 'Phoenix Force'

SuperheroView

moderate

superhero

Identify the heaviest superhero in DC Comics.

heaviest refers to MAX(weight_kg); DC Comics refers to publisher_name = 'DC Comics'; superhero refers to superhero_name;

SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T2.publisher_name = 'DC Comics' ORDER BY T1.weight_kg DESC LIMIT 1

SuperheroView

simple

superhero

What is the average height of a non-human superhero in Dark Horse Comics?

average = AVG(height_cm); non-human superhero refers to race <> 'Human'; Dark Horse Comics refers to publisher_name = 'Dark Horse Comics';

SELECT AVG(T1.height_cm) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN race AS T3 ON T1.race_id = T3.id WHERE T2.publisher_name = 'Dark Horse Comics' AND T3.race != 'Human'

SuperheroView

filter_by_publisher_name("Dark Horse Comics") AND NOT filter_by_race("Human")

average_height()

moderate

superhero

Count the fastest superheroes.

fastest refers to attribute_value = 100 WHERE attribute_name = 'Speed';

SELECT COUNT(T3.superhero_name) FROM hero_attribute AS T1 INNER JOIN attribute AS T2 ON T1.attribute_id = T2.id INNER JOIN superhero AS T3 ON T1.hero_id = T3.id WHERE T2.attribute_name = 'Speed' AND T1.attribute_value = 100

SuperheroView

count_superheroes()

simple

superhero

Which publisher created more superheroes: DC or Marvel Comics? Find the difference in the number of superheroes.

DC refers to publisher_name = 'DC Comics'; Marvel Comics refers to publisher_name = 'Marvel Comics'; difference = SUBTRACT(SUM(publisher_name = 'DC Comics'), SUM(publisher_name = 'Marvel Comics'));

SELECT SUM(CASE WHEN T2.publisher_name = 'DC Comics' THEN 1 ELSE 0 END) - SUM(CASE WHEN T2.publisher_name = 'Marvel Comics' THEN 1 ELSE 0 END) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id

SuperheroView

challenging

superhero

Identify the weakest attribute of the Black Panther.

weakest attribute refers to attribute_name WHERE MIN(attribute_value); Black Panther refers to superhero_name = 'Black Panther';

SELECT T3.attribute_name FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id INNER JOIN attribute AS T3 ON T2.attribute_id = T3.id WHERE T1.superhero_name = 'Black Panther' ORDER BY T2.attribute_value ASC LIMIT 1

moderate

superhero

What is Abomination's eye colour?

Abomination refers to superhero_name = 'Abomination'; eye colour refers to colour.colour where eye_colour_id = colour.id;

SELECT T2.colour FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T1.superhero_name = 'Abomination'

SuperheroView

filter_by_superhero_name("Abomination")

simple

superhero

Name the tallest superhero.

tallest superhero refers to MAX(height_cm);

SELECT superhero_name FROM superhero ORDER BY height_cm DESC LIMIT 1

SuperheroView

filter_by_the_tallest()

simple

superhero

Name the superhero, otherwise known as Charles Chandler.

name the superhero refers to superhero_name; Charles Chandler is the full name of superhero;

SELECT superhero_name FROM superhero WHERE full_name = 'Charles Chandler'

SuperheroView

filter_by_superhero_full_name("Charles Chandler")

simple

superhero

Among all superheroes created by George Lucas, identify the percentage of female superheroes.

created by George Lucas refers to publisher_name = 'George Lucas'; percentage = MULTIPLY(DIVIDE(SUM(gender = 'Female' WHERE publisher_name = 'George Lucas'), COUNT(publisher_name = 'George Lucas')), 100.0); female refers to gender = 'Female';

SELECT CAST(COUNT(CASE WHEN T3.gender = 'Female' THEN 1 ELSE NULL END) AS REAL) * 100 / COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN gender AS T3 ON T1.gender_id = T3.id WHERE T2.publisher_name = 'George Lucas'

SuperheroView

filter_by_publisher_name("George Lucas")

percentage_of_gender("Female")

challenging

superhero

Among all superheroes in Marvel Comics, identify the percentage of 'good' superheroes.

Marvel Comics refers to publisher_name = 'Marvel Comics'; percentage = MULTIPLY(DIVIDE(SUM(alignment = 'Good' WHERE publisher_name = 'Marvel Comics'), COUNT(publisher_name = 'Marvel Comics')), 100.0); good superheroes refers to alignment = 'Good';

SELECT CAST(COUNT(CASE WHEN T3.alignment = 'Good' THEN T1.id ELSE NULL END) AS REAL) * 100 / COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN alignment AS T3 ON T1.alignment_id = T3.id WHERE T2.publisher_name = 'Marvel Comics'

SuperheroView

filter_by_publisher_name("Marvel Comics")

challenging

superhero

What is the total number of superheroes that have John as their first name?

have John as their first name refers to full_name LIKE 'John%';

SELECT COUNT(id) FROM superhero WHERE full_name LIKE 'John%'

SuperheroView

filter_by_superhero_first_name("John")

count_superheroes()

simple

superhero

Give the hero ID of superhero with the lowest attribute value.

lowest attribute value refers to MIN(attribute_value);

SELECT hero_id FROM hero_attribute WHERE attribute_value = ( SELECT MIN(attribute_value) FROM hero_attribute )

SuperheroView

simple

superhero

Provide the full name of the superhero named Alien.

SELECT full_name FROM superhero WHERE superhero_name = 'Alien'

SuperheroView

filter_by_superhero_name("Alien")

simple

superhero

In superheroes with weight less than 100, list the full name of the superheroes with brown eyes.

weight less than 100 refers to weight_kg < 100

SELECT T1.full_name FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T1.weight_kg < 100 AND T2.colour = 'Brown'

SuperheroView

filter_by_weight_kg_less_than(100) AND filter_by_eye_colour("Brown")

simple

superhero

List the attribute value of the superhero named Aquababy.

SELECT T2.attribute_value FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id WHERE T1.superhero_name = 'Aquababy'

simple

superhero

Provide the weight and race of the superhero with superhero ID 40.

weight refers to weight_kg; superhero ID 40 refers to superhero.id = 40;

SELECT T1.weight_kg, T2.race FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id WHERE T1.id = 40

SuperheroView

filter_by_superhero_id(40)

simple

superhero

Calculate the average height of all neutral superheroes.

SELECT AVG(T1.height_cm) FROM superhero AS T1 INNER JOIN alignment AS T2 ON T1.alignment_id = T2.id WHERE T2.alignment = 'Neutral'

SuperheroView

filter_by_alignment("Neutral")

average_height()

simple

superhero

List the hero ID of superheroes have intellegence as their power.

hero ID refers to superhero.id; have intelligence as their power refers to power_name = 'Intelligence';

SELECT T1.hero_id FROM hero_power AS T1 INNER JOIN superpower AS T2 ON T1.power_id = T2.id WHERE T2.power_name = 'Intelligence'

SuperheroView

simple

superhero

Give the eye colour of Blackwulf.

eye colour refers to colour.colour where eye_colour_id = colour.id; Blackwulf refers to superhero_name = 'Blackwulf';

SELECT T2.colour FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T1.superhero_name = 'Blackwulf'

SuperheroView

filter_by_superhero_name("Blackwulf")

simple

superhero

List the power of superheroes with height greater than 80% of the average height of all superheroes.

power of superheroes refers to power_name; height greater than 80% of the average height of all superheroes = height_cm > MULTIPLY(AVG(height_cm), 0.8);

SELECT T3.power_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T1.height_cm * 100 > ( SELECT AVG(height_cm) FROM superhero ) * 80

moderate